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Iosif Pinelis
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Consider a diffusion given by $$X_t=\int_0^t a(s,X_s)\,dW_s$$ for $t\ge 0$, where $W_\cdot$ is a standard Wiener process/Brownian motion and $a$ is a smooth enough positive function bounded away from $0$.

Does then $X_1$ have a bounded pdf?


This interesting answer by James Martin shows that, without assuming that $a$ is bounded away from $0$ and replacing $a(s,X_s)$ by $a\big(s,(X_u\colon 0\le u\le s)\big)$, it is possible that $P(X_1=0)>0$. See also comments to that answer.

Consider a diffusion given by $$X_t=\int_0^t a(s,X_s)\,dW_s$$ for $t\ge 0$, where $W_\cdot$ is a standard Wiener process/Brownian motion and $a$ is a smooth enough positive function bounded away from $0$.

Does then $X_1$ have a bounded pdf?


This interesting answer by James Martin shows that, without assuming that $a$ is bounded away from $0$, it is possible that $P(X_1=0)>0$. See also comments to that answer.

Consider a diffusion given by $$X_t=\int_0^t a(s,X_s)\,dW_s$$ for $t\ge 0$, where $W_\cdot$ is a standard Wiener process/Brownian motion and $a$ is a smooth enough positive function bounded away from $0$.

Does then $X_1$ have a bounded pdf?


This interesting answer by James Martin shows that, without assuming that $a$ is bounded away from $0$ and replacing $a(s,X_s)$ by $a\big(s,(X_u\colon 0\le u\le s)\big)$, it is possible that $P(X_1=0)>0$. See also comments to that answer.

Source Link
Iosif Pinelis
  • 127.7k
  • 8
  • 107
  • 229

Bounded density for diffusions with diffusion coefficients bounded away from $0$

Consider a diffusion given by $$X_t=\int_0^t a(s,X_s)\,dW_s$$ for $t\ge 0$, where $W_\cdot$ is a standard Wiener process/Brownian motion and $a$ is a smooth enough positive function bounded away from $0$.

Does then $X_1$ have a bounded pdf?


This interesting answer by James Martin shows that, without assuming that $a$ is bounded away from $0$, it is possible that $P(X_1=0)>0$. See also comments to that answer.