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Logarithmic -> logarithm, while this is on the front page
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LSpice
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On integral relating logarithmiclogarithm of absolute value of Zeta function:

Sorry for such a direct question:

Consider the following integral:

$$I(t)=\int_{1/2}^{1} {\log|\zeta(a+it)|}da$$$$I(t)=\int_{1/2}^{1} {\log|\zeta(a+it)|}da.$$

How to find the nature of $I(t)$ as $t\rightarrow\infty$?

On integral relating logarithmic of absolute value of Zeta function:

Sorry for such a direct question:

Consider the following integral:

$$I(t)=\int_{1/2}^{1} {\log|\zeta(a+it)|}da$$

How to find the nature of $I(t)$ as $t\rightarrow\infty$?

On integral relating logarithm of absolute value of Zeta function

Sorry for such a direct question:

Consider the following integral:

$$I(t)=\int_{1/2}^{1} {\log|\zeta(a+it)|}da.$$

How to find the nature of $I(t)$ as $t\rightarrow\infty$?

Bumped by Community user
Bumped by Community user
Bumped by Community user
Bumped by Community user
Bumped by Community user
Bumped by Community user
Bumped by Community user
Bumped by Community user
Bumped by Community user
edited body
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TPC
  • 790
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Sorry for such a direct question:

Consider the following integral:

$$I(t)=\int_{1/2}^{1} {\log|\zeta(a+it)|}da$$

How to find the nature of $I(t)$ as $a\rightarrow\infty$$t\rightarrow\infty$?

Sorry for such a direct question:

Consider the following integral:

$$I(t)=\int_{1/2}^{1} {\log|\zeta(a+it)|}da$$

How to find the nature of $I(t)$ as $a\rightarrow\infty$?

Sorry for such a direct question:

Consider the following integral:

$$I(t)=\int_{1/2}^{1} {\log|\zeta(a+it)|}da$$

How to find the nature of $I(t)$ as $t\rightarrow\infty$?

Source Link
TPC
  • 790
  • 5
  • 14

On integral relating logarithmic of absolute value of Zeta function:

Sorry for such a direct question:

Consider the following integral:

$$I(t)=\int_{1/2}^{1} {\log|\zeta(a+it)|}da$$

How to find the nature of $I(t)$ as $a\rightarrow\infty$?