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Jul 19, 2020 at 5:38 answer added Neil Hoffman timeline score: 1
Jul 8, 2020 at 12:00 answer added Oğuz Şavk timeline score: 1
Jul 8, 2020 at 7:15 answer added Sam Nead timeline score: 3
Jul 7, 2020 at 22:29 answer added Kyle Hayden timeline score: 7
Jul 7, 2020 at 9:01 vote accept CommunityBot
Jul 7, 2020 at 8:31 comment added user160180 Yes, I'm looking for an orientation-preserving homeomorphism.
Jul 7, 2020 at 1:58 comment added Kyle Hayden So, just to clarify, you want an orientation-preserving homeomorphism?
Jul 3, 2020 at 17:52 answer added Ian Agol timeline score: 6
Jul 3, 2020 at 17:25 history edited user160180 CC BY-SA 4.0
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Jul 1, 2020 at 14:23 comment added Marco Golla @MaximUlyanov: I suppose so. Actually, I think that my proof is just deriving the Rolfsen twist. You can blow up the clasp on the top left of the left-most diagram, and then do a Rolfsen twist of the -1/3-framed curve (which is now unknotted). See Figure 5.27 in Gompf and Stipsicz, for instance.
Jul 1, 2020 at 13:15 comment added user160180 @MarcoGolla I just saw the Rolfsen's rational surgery calculus. Is it possible to do this proof with it?
Jul 1, 2020 at 13:13 comment added user160180 @MarcoGolla Yes. I had a problem with Gmail account. I closed and reopened it a week ago.
Jul 1, 2020 at 13:04 comment added Marco Golla By the way: Maxim, didn't you have another account?
Jul 1, 2020 at 12:40 vote accept CommunityBot
Jul 3, 2020 at 20:12
Jul 1, 2020 at 12:37 answer added Marco Golla timeline score: 20
Jul 1, 2020 at 11:59 comment added user160180 They are the $3$-manifolds are respectively obtained by $-1/3$ and $1$-surgeries on the knots in the figure.
Jul 1, 2020 at 11:54 comment added YCor I guess that "the following 3-manifolds", means the knot complements?
Jul 1, 2020 at 11:31 history asked user160180 CC BY-SA 4.0