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On some integral involving the LiovilleLiouville sum

Define $L(x) = \sum_{n\leq x} \lambda(n)$, where $\lambda$ denotes the Lioville functionLiouville function. If $c$ is the supremum of the real parts of the zeros of the Riemann zeta function and $[x]$$\lfloor x\rfloor$ denotes the integer part of $x$, is it true that

$$\Big|\int_{1}^{x} L(y) [x/y] \frac{\mathrm{d}y}{y} \Big| > x^{c-\epsilon}$$ $$\Bigl\lvert\int_{1}^{x} L(y)\lfloor x/y\rfloor\frac{\mathrm{d}y}{y} \Bigr\rvert > x^{c-\epsilon}$$ for arbitrarily large $x$ and any $\epsilon>0$  ?

On some integral involving the Lioville sum

Define $L(x) = \sum_{n\leq x} \lambda(n)$, where $\lambda$ denotes the Lioville function. If $c$ is the supremum of the real parts of the zeros of the Riemann zeta function and $[x]$ denotes the integer part of $x$, is it true that

$$\Big|\int_{1}^{x} L(y) [x/y] \frac{\mathrm{d}y}{y} \Big| > x^{c-\epsilon}$$ for arbitrarily large $x$ and any $\epsilon>0$  ?

On some integral involving the Liouville sum

Define $L(x) = \sum_{n\leq x} \lambda(n)$, where $\lambda$ denotes the Liouville function. If $c$ is the supremum of the real parts of the zeros of the Riemann zeta function and $\lfloor x\rfloor$ denotes the integer part of $x$, is it true that $$\Bigl\lvert\int_{1}^{x} L(y)\lfloor x/y\rfloor\frac{\mathrm{d}y}{y} \Bigr\rvert > x^{c-\epsilon}$$ for arbitrarily large $x$ and any $\epsilon>0$?

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Q_p
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On some integral involving the Lioville sum

Define $L(x) = \sum_{n\leq x} \lambda(n)$, where $\lambda$ denotes the Lioville function. If $c$ is the supremum of the real parts of the zeros of the Riemann zeta function and $[x]$ denotes the integer part of $x$, is it true that

$$\Big|\int_{1}^{x} L(y) [x/y] \frac{\mathrm{d}y}{y} \Big| > x^{c-\epsilon}$$ for arbitrarily large $x$ and any $\epsilon>0$ ?