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Conclusion and questions##questions

Conclusion and questions##

Conclusion and questions

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Parabolic case

I have considered the following scenarios, first:

$$g(t) = \frac{t^2}{2}$$

with the conditions being

$$\partial_t |\psi_0|^2 = 0$$ and $$\partial_x |\psi_0|^2 + \partial_t^2 |\psi_0|^2 = 0$$

From the first condition $\partial_t |\psi_0|^2 = 0$ I took only the case where $\psi_0 = \psi_0^*$. Adding this to the second condition I got

$$\psi_0 \partial_x^4 \psi_0 + \psi_0 \partial_x \psi_0 - (\partial_x^2 \psi_0)^2 = 0$$

I used a discrete version of this ODE and have computed the initial condition $\psi_0$ using

$$\psi_0^{m+4} = 4\psi_0^{m+3} - 6 \psi_0^{m+2} + 4 \psi_0^{m+1} - \psi_0^{m} + \frac{(\psi_0^{m+3}-2\psi_0^{m+2}+\psi_0^{m+1})^2}{\psi_0^{m+2}} - \Delta x^3(\psi_0^{m+3} - \psi_0^{m+1})$$

and some initial values for $\psi_0^{m=0..3}$ that I chose myself. After a few attempts with the values for $\psi_0^{m=0..3}$, I got to some values that generated the initial condition for the solution that is plotted in the figure.

I have also tested for $g(t) = t$ and managed to change the angle between the "trajectory" a Gaussian beam propagates compared to the propagation axis.

This means that the method works for those cases and probably works for superior orders, but I have not tested them yet.

I consider this question closed.

Update

Parabolic case

I have considered the following scenarios, first:

$$g(t) = \frac{t^2}{2}$$

with the conditions being

$$\partial_t |\psi_0|^2 = 0$$ and $$\partial_x |\psi_0|^2 + \partial_t^2 |\psi_0|^2 = 0$$

From the first condition $\partial_t |\psi_0|^2 = 0$ I took only the case where $\psi_0 = \psi_0^*$. Adding this to the second condition I got

$$\psi_0 \partial_x^4 \psi_0 + \psi_0 \partial_x \psi_0 - (\partial_x^2 \psi_0)^2 = 0$$

I used a discrete version of this ODE and have computed the initial condition $\psi_0$ using

$$\psi_0^{m+4} = 4\psi_0^{m+3} - 6 \psi_0^{m+2} + 4 \psi_0^{m+1} - \psi_0^{m} + \frac{(\psi_0^{m+3}-2\psi_0^{m+2}+\psi_0^{m+1})^2}{\psi_0^{m+2}} - \Delta x^3(\psi_0^{m+3} - \psi_0^{m+1})$$

and some initial values for $\psi_0^{m=0..3}$ that I chose myself. After a few attempts with the values for $\psi_0^{m=0..3}$, I got to some values that generated the initial condition for the solution that is plotted in the figure.

I have also tested for $g(t) = t$ and managed to change the angle between the "trajectory" a Gaussian beam propagates compared to the propagation axis.

This means that the method works for those cases and probably works for superior orders, but I have not tested them yet.

I consider this question closed.

added a top-level tag; https://meta.mathoverflow.net/questions/1457/why-are-mo-tags-formatted-as-they-are
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Martin Sleziak
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I know the values of $\partial_t^n g(t=0), \forall n \in \mathbb{N}$ since I chose $g(t) = x_0 + t^2/2$, so I can derivate the condition with respect to $t$ in order to get to each $\partial_t^n g(t=0)$ term after I evaluate the expresionexpression at $t=0$.

I know the values of $\partial_t^n g(t=0), \forall n \in \mathbb{N}$ since I chose $g(t) = x_0 + t^2/2$, so I can derivate the condition with respect to $t$ in order to get to each $\partial_t^n g(t=0)$ term after I evaluate the expresion at $t=0$.

I know the values of $\partial_t^n g(t=0), \forall n \in \mathbb{N}$ since I chose $g(t) = x_0 + t^2/2$, so I can derivate the condition with respect to $t$ in order to get to each $\partial_t^n g(t=0)$ term after I evaluate the expression at $t=0$.

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