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Assumed that $M$ is simply connected
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Giulio
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Let $M$ be a simply connected complex manifold (of dimension greater than one), $L$ a line bundle, and $\Delta$$\nabla$ a connection on $L$ with possibly singularities along a divisor $D$. We define the curvature as $$ R_{\Delta}(X,Y)=[\Delta_X,\Delta_Y]-\Delta_{[X,Y]} $$$$ R_{\nabla}(X,Y)=[\nabla_X,\nabla_Y]-\nabla_{[X,Y]} $$

Suppose that a second connection $\Delta'$$\nabla'$ on $L$ has the same singularities and the same curvature. Is $\Delta$$\nabla$ equal to $\Delta'$$\nabla'$?

Let $M$ be a complex manifold (of dimension greater than one), $L$ a line bundle, and $\Delta$ a connection on $L$ with possibly singularities along a divisor $D$. We define the curvature as $$ R_{\Delta}(X,Y)=[\Delta_X,\Delta_Y]-\Delta_{[X,Y]} $$

Suppose that a second connection $\Delta'$ on $L$ has the same singularities and the same curvature. Is $\Delta$ equal to $\Delta'$?

Let $M$ be a simply connected complex manifold (of dimension greater than one), $L$ a line bundle, and $\nabla$ a connection on $L$ with possibly singularities along a divisor $D$. We define the curvature as $$ R_{\nabla}(X,Y)=[\nabla_X,\nabla_Y]-\nabla_{[X,Y]} $$

Suppose that a second connection $\nabla'$ on $L$ has the same singularities and the same curvature. Is $\nabla$ equal to $\nabla'$?

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Giulio
  • 2.4k
  • 12
  • 20

Does the holomorphic curvature determine the connection?

Let $M$ be a complex manifold (of dimension greater than one), $L$ a line bundle, and $\Delta$ a connection on $L$ with possibly singularities along a divisor $D$. We define the curvature as $$ R_{\Delta}(X,Y)=[\Delta_X,\Delta_Y]-\Delta_{[X,Y]} $$

Suppose that a second connection $\Delta'$ on $L$ has the same singularities and the same curvature. Is $\Delta$ equal to $\Delta'$?