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Quote-boxed the conjecture, and hid the link because links are ugly.
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Conjecture: Let $f:\mathbb{R}→\mathbb{R}$ be an everywhere differentiable function and assume that $f(x)+f′(x)∈ \{-1,1\}$ almost everywhere and $f'(0)=0$. Then is f necessarily a constant function?

Conjecture: Let $f:\mathbb{R}→\mathbb{R}$ be an everywhere differentiable function and assume that $f(x)+f′(x)∈ \{-1,1\}$ almost everywhere and $f'(0)=0$. Then is $f$ necessarily a constant function?

Can you give me a counter-example  ?

  I have already asked the question here https://math.stackexchange.com/questions/2859868/differential-equation-changing-sign-almost-everywherehere on MathSE.

Conjecture: Let $f:\mathbb{R}→\mathbb{R}$ be an everywhere differentiable function and assume that $f(x)+f′(x)∈ \{-1,1\}$ almost everywhere and $f'(0)=0$. Then is f necessarily a constant function?

Can you give me a counter-example  ?

  I have already asked the question here https://math.stackexchange.com/questions/2859868/differential-equation-changing-sign-almost-everywhere

Conjecture: Let $f:\mathbb{R}→\mathbb{R}$ be an everywhere differentiable function and assume that $f(x)+f′(x)∈ \{-1,1\}$ almost everywhere and $f'(0)=0$. Then is $f$ necessarily a constant function?

Can you give me a counter-example? I have already asked the question here on MathSE.

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Paul
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Differential equation changing sign almost everywhere

Conjecture: Let $f:\mathbb{R}→\mathbb{R}$ be an everywhere differentiable function and assume that $f(x)+f′(x)∈ \{-1,1\}$ almost everywhere and $f'(0)=0$. Then is f necessarily a constant function?

Can you give me a counter-example ?

I have already asked the question here https://math.stackexchange.com/questions/2859868/differential-equation-changing-sign-almost-everywhere