Question. Let $\sf{AI}_{\kappa}$ (Arrow's Impossibility for $\kappa$ voters) denote the assertation that the axioms (A1)-(A4) are inconsistent under the condition $|\sf{Voters}$$|=\kappa$. As a summary of the mentioned results by Arrow, Fishburn, Litak and Woodin, we know:
$\sf{ZF}$$~\vdash \forall n\in [1,\aleph_0) ~~~$$\sf{AI}_{n}$
$\sf{ZF+AC}$$~\vdash \neg $$\sf{AI}_{\aleph_0}$
$\sf{ZF+AD}$$~\vdash$$~\sf{AI}_{\aleph_0}$
$\sf{Con(ZFC+\text{$\omega$-many Woodin cardinals and a measurable above them})}$$\Rightarrow$$\sf{Con(ZF+\sf{AI}_{\aleph_0})}$
The questions simply are:
$\sf{Con(ZFC+\text{?})}$$\Rightarrow$$\sf{Con(ZF+\forall \kappa\in Card^{>0}~~~ \sf{AI}_{\kappa})}$
$\sf{Con(ZFC+\text{?})}$$\Rightarrow$$\sf{Con(ZF+\exists \kappa\geq \aleph_{1}~~~ \sf{AI}_{\kappa})}$
In other words:
- What is the consistency strength of having Arrow's Impossibility Theorem in societies of arbitrarily large size in the absence of the Axiom of Choice?
What is the consistency strength of having Arrow's Impossibility Theorem in societies of arbitrarily large size in the absence of the Axiom of Choice?
Define an Arrow cardinal to be an uncountable cardinal $\kappa$ which $\sf{AI}_{\kappa}$ holds. What is the consistency strength of having at least one such cardinal in the absence of $\sf{AC}$?
- Define an Arrow cardinal to be an uncountable cardinal $\kappa$ which $\sf{AI}_{\kappa}$ holds. What is the consistency strength of having at least one such cardinal in the absence of $\sf{AC}$?