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I have athe following quadratic matrix equation in symmetric positive semidefinite covariance matrix $\mathbf{C}$

$$ \mathbf{C}\mathbf{S}\mathbf{C}+\mathbf{C}+\mathbf{A}=\mathbf{0} $$$$\mathbf{C}\mathbf{S}\mathbf{C}+\mathbf{C}+\mathbf{A}=\mathbf{0}$$

Where $\mathbf{C}$ is a covariance matrix (symmetric, positive semi definite),where $\mathbf{S}$ is a singular matrix and $\mathbf{A}$ is some matrix of the form $\mathbf{A}=a*a^{T}$ (Product of a column vector with its transpose)$\mathbf{A} = \mathbf{a} \mathbf{a}^{T}$. I need to iteratively find $\mathbf{C}$.

  1. If I try to set up the problem using Bernoulli iteration, in order to find the dominant solvent I would have to go for

$$ \mathbf{S}+\{\mathbf{I}+\mathbf{C}_{k}^{-1}\mathbf{A}\}*\mathbf{C}_{k+1}^{-1} = \mathbf{0} $$

$$ \Longrightarrow \mathbf{C}_{k+1}^{-1} = \{\mathbf{I}+\mathbf{C}_{k}^{-1}\mathbf{A}\}^{-1}*(-\mathbf{S}) $$

Which won't make sense since $\mathbf{S}$ is singular

  1. If I try to to find the minimal solvent, I set it up as

$$ (\mathbf{C}_{k}\mathbf{S}+\mathbf{I})*\mathbf{C}_{k+1}+\mathbf{A}=\mathbf{0} $$

$$ \Longrightarrow \mathbf{C}_{k+1}=(\mathbf{C}_{k}\mathbf{S}+\mathbf{I})^{-1}*(-\mathbf{A}) $$

But this doesn't seem to be working either.

  1. A last, non-Bernoulli iteration I set up was

$$ \mathbf{C}_{k}\mathbf{S}\mathbf{C}_{k}+\mathbf{C}_{k+1}+\mathbf{A}=\mathbf{0} $$

$$ \Longrightarrow \mathbf{C}_{k+1}=-\mathbf{A}-\mathbf{C}_{k}\mathbf{S}\mathbf{C}_{k} $$

Which seems to be working but I'm not sure which root it converges to. Also the final estimate $\mathbf{C}_{k}$ converges to, somehow appears to be twice the actual value (upon performing a ground truth test).

My queries are

1- Am I on the right track on dealing with this problem? If so, where am I making mistakes?

2- Is there any procedure to find the dominant and minimal solvent when the coefficient of the square term is singular?

3- Is the last, non-Bernoulli iteration valid? If so, why is the result twice the actual one? Which root does it converge to?

  1. Am I on the right track on dealing with this problem? If so, where am I making mistakes?

  2. Is there any procedure to find the dominant and minimal solvent when the coefficient of the square term is singular?

  3. Is the last, non-Bernoulli iteration valid? If so, why is the result twice the actual one? Which root does it converge to?

Any guidance will be highly appreciated. Thank you.

I have a quadratic matrix equation

$$ \mathbf{C}\mathbf{S}\mathbf{C}+\mathbf{C}+\mathbf{A}=\mathbf{0} $$

Where $\mathbf{C}$ is a covariance matrix (symmetric, positive semi definite), $\mathbf{S}$ is a singular matrix and $\mathbf{A}$ is some matrix of the form $\mathbf{A}=a*a^{T}$ (Product of a column vector with its transpose). I need to iteratively find $\mathbf{C}$

  1. If I try to set up the problem using Bernoulli iteration, in order to find the dominant solvent I would have to go for

$$ \mathbf{S}+\{\mathbf{I}+\mathbf{C}_{k}^{-1}\mathbf{A}\}*\mathbf{C}_{k+1}^{-1} = \mathbf{0} $$

$$ \Longrightarrow \mathbf{C}_{k+1}^{-1} = \{\mathbf{I}+\mathbf{C}_{k}^{-1}\mathbf{A}\}^{-1}*(-\mathbf{S}) $$

Which won't make sense since $\mathbf{S}$ is singular

  1. If I try to to find the minimal solvent, I set it up as

$$ (\mathbf{C}_{k}\mathbf{S}+\mathbf{I})*\mathbf{C}_{k+1}+\mathbf{A}=\mathbf{0} $$

$$ \Longrightarrow \mathbf{C}_{k+1}=(\mathbf{C}_{k}\mathbf{S}+\mathbf{I})^{-1}*(-\mathbf{A}) $$

But this doesn't seem to be working either.

  1. A last, non-Bernoulli iteration I set up was

$$ \mathbf{C}_{k}\mathbf{S}\mathbf{C}_{k}+\mathbf{C}_{k+1}+\mathbf{A}=\mathbf{0} $$

$$ \Longrightarrow \mathbf{C}_{k+1}=-\mathbf{A}-\mathbf{C}_{k}\mathbf{S}\mathbf{C}_{k} $$

Which seems to be working but I'm not sure which root it converges to. Also the final estimate $\mathbf{C}_{k}$ converges to, somehow appears to be twice the actual value (upon performing a ground truth test).

My queries are

1- Am I on the right track on dealing with this problem? If so, where am I making mistakes?

2- Is there any procedure to find the dominant and minimal solvent when the coefficient of the square term is singular?

3- Is the last, non-Bernoulli iteration valid? If so, why is the result twice the actual one? Which root does it converge to?

Any guidance will be highly appreciated. Thank you.

I have the following quadratic matrix equation in symmetric positive semidefinite covariance matrix $\mathbf{C}$

$$\mathbf{C}\mathbf{S}\mathbf{C}+\mathbf{C}+\mathbf{A}=\mathbf{0}$$

where $\mathbf{S}$ is a singular matrix and $\mathbf{A} = \mathbf{a} \mathbf{a}^{T}$. I need to iteratively find $\mathbf{C}$.

  1. If I try to set up the problem using Bernoulli iteration, in order to find the dominant solvent I would have to go for

$$ \mathbf{S}+\{\mathbf{I}+\mathbf{C}_{k}^{-1}\mathbf{A}\}*\mathbf{C}_{k+1}^{-1} = \mathbf{0} $$

$$ \Longrightarrow \mathbf{C}_{k+1}^{-1} = \{\mathbf{I}+\mathbf{C}_{k}^{-1}\mathbf{A}\}^{-1}*(-\mathbf{S}) $$

Which won't make sense since $\mathbf{S}$ is singular

  1. If I try to to find the minimal solvent, I set it up as

$$ (\mathbf{C}_{k}\mathbf{S}+\mathbf{I})*\mathbf{C}_{k+1}+\mathbf{A}=\mathbf{0} $$

$$ \Longrightarrow \mathbf{C}_{k+1}=(\mathbf{C}_{k}\mathbf{S}+\mathbf{I})^{-1}*(-\mathbf{A}) $$

But this doesn't seem to be working either.

  1. A last, non-Bernoulli iteration I set up was

$$ \mathbf{C}_{k}\mathbf{S}\mathbf{C}_{k}+\mathbf{C}_{k+1}+\mathbf{A}=\mathbf{0} $$

$$ \Longrightarrow \mathbf{C}_{k+1}=-\mathbf{A}-\mathbf{C}_{k}\mathbf{S}\mathbf{C}_{k} $$

Which seems to be working but I'm not sure which root it converges to. Also the final estimate $\mathbf{C}_{k}$ converges to, somehow appears to be twice the actual value (upon performing a ground truth test).

My queries are

  1. Am I on the right track on dealing with this problem? If so, where am I making mistakes?

  2. Is there any procedure to find the dominant and minimal solvent when the coefficient of the square term is singular?

  3. Is the last, non-Bernoulli iteration valid? If so, why is the result twice the actual one? Which root does it converge to?

Any guidance will be highly appreciated. Thank you.

edited body
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I have a quadratic matrix equation

$$ \mathbf{C}\mathbf{S}\mathbf{C}+\mathbf{C}+\mathbf{A}=\mathbf{0} $$

Where $\mathbf{C}$ is a covariance matrix (symmetric, positive semi definite), $\mathbf{S}$ is a singular matrix and $\mathbf{A}$ is some matrix of the form $\mathbf{A}=a*a^{T}$ (Product of a column vector with its transpose). I need to iteratively find $\mathbf{C}$

  1. If I try to set up the problem using Bernoulli iteration, in order to find the dominant solvent I would have to go for

$$ \mathbf{S}+\{\mathbf{I}+\mathbf{C}_{k}^{-1}\mathbf{S}\}*\mathbf{C}_{k+1}^{-1} = \mathbf{0} $$$$ \mathbf{S}+\{\mathbf{I}+\mathbf{C}_{k}^{-1}\mathbf{A}\}*\mathbf{C}_{k+1}^{-1} = \mathbf{0} $$

$$ \Longrightarrow \mathbf{C}_{k+1}^{-1} = \{\mathbf{I}+\mathbf{C}_{k}^{-1}\mathbf{S}\}^{-1}*(-\mathbf{S}) $$$$ \Longrightarrow \mathbf{C}_{k+1}^{-1} = \{\mathbf{I}+\mathbf{C}_{k}^{-1}\mathbf{A}\}^{-1}*(-\mathbf{S}) $$

Which won't make sense since $\mathbf{S}$ is singular

  1. If I try to to find the minimal solvent, I set it up as

$$ (\mathbf{C}_{k}\mathbf{S}+\mathbf{I})*\mathbf{C}_{k+1}+\mathbf{A}=\mathbf{0} $$

$$ \Longrightarrow \mathbf{C}_{k+1}=(\mathbf{C}_{k}\mathbf{S}+\mathbf{I})^{-1}*(-\mathbf{A}) $$

But this doesn't seem to be working either.

  1. A last, non-Bernoulli iteration I set up was

$$ \mathbf{C}_{k}\mathbf{S}\mathbf{C}_{k}+\mathbf{C}_{k+1}+\mathbf{A}=\mathbf{0} $$

$$ \Longrightarrow \mathbf{C}_{k+1}=-\mathbf{A}-\mathbf{C}_{k}\mathbf{S}\mathbf{C}_{k} $$

Which seems to be working but I'm not sure which root it converges to. Also the final estimate $\mathbf{C}_{k}$ converges to, somehow appears to be twice the actual value (upon performing a ground truth test).

My queries are

1- Am I on the right track on dealing with this problem? If so, where am I making mistakes?

2- Is there any procedure to find the dominant and minimal solvent when the coefficient of the square term is singular?

3- Is the last, non-Bernoulli iteration valid? If so, why is the result twice the actual one? Which root does it converge to?

Any guidance will be highly appreciated. Thank you.

I have a quadratic matrix equation

$$ \mathbf{C}\mathbf{S}\mathbf{C}+\mathbf{C}+\mathbf{A}=\mathbf{0} $$

Where $\mathbf{C}$ is a covariance matrix (symmetric, positive semi definite), $\mathbf{S}$ is a singular matrix and $\mathbf{A}$ is some matrix of the form $\mathbf{A}=a*a^{T}$ (Product of a column vector with its transpose). I need to iteratively find $\mathbf{C}$

  1. If I try to set up the problem using Bernoulli iteration, in order to find the dominant solvent I would have to go for

$$ \mathbf{S}+\{\mathbf{I}+\mathbf{C}_{k}^{-1}\mathbf{S}\}*\mathbf{C}_{k+1}^{-1} = \mathbf{0} $$

$$ \Longrightarrow \mathbf{C}_{k+1}^{-1} = \{\mathbf{I}+\mathbf{C}_{k}^{-1}\mathbf{S}\}^{-1}*(-\mathbf{S}) $$

Which won't make sense since $\mathbf{S}$ is singular

  1. If I try to to find the minimal solvent, I set it up as

$$ (\mathbf{C}_{k}\mathbf{S}+\mathbf{I})*\mathbf{C}_{k+1}+\mathbf{A}=\mathbf{0} $$

$$ \Longrightarrow \mathbf{C}_{k+1}=(\mathbf{C}_{k}\mathbf{S}+\mathbf{I})^{-1}*(-\mathbf{A}) $$

But this doesn't seem to be working either.

  1. A last, non-Bernoulli iteration I set up was

$$ \mathbf{C}_{k}\mathbf{S}\mathbf{C}_{k}+\mathbf{C}_{k+1}+\mathbf{A}=\mathbf{0} $$

$$ \Longrightarrow \mathbf{C}_{k+1}=-\mathbf{A}-\mathbf{C}_{k}\mathbf{S}\mathbf{C}_{k} $$

Which seems to be working but I'm not sure which root it converges to. Also the final estimate $\mathbf{C}_{k}$ converges to, somehow appears to be twice the actual value (upon performing a ground truth test).

My queries are

1- Am I on the right track on dealing with this problem? If so, where am I making mistakes?

2- Is there any procedure to find the dominant and minimal solvent when the coefficient of the square term is singular?

3- Is the last, non-Bernoulli iteration valid? If so, why is the result twice the actual one? Which root does it converge to?

Any guidance will be highly appreciated. Thank you.

I have a quadratic matrix equation

$$ \mathbf{C}\mathbf{S}\mathbf{C}+\mathbf{C}+\mathbf{A}=\mathbf{0} $$

Where $\mathbf{C}$ is a covariance matrix (symmetric, positive semi definite), $\mathbf{S}$ is a singular matrix and $\mathbf{A}$ is some matrix of the form $\mathbf{A}=a*a^{T}$ (Product of a column vector with its transpose). I need to iteratively find $\mathbf{C}$

  1. If I try to set up the problem using Bernoulli iteration, in order to find the dominant solvent I would have to go for

$$ \mathbf{S}+\{\mathbf{I}+\mathbf{C}_{k}^{-1}\mathbf{A}\}*\mathbf{C}_{k+1}^{-1} = \mathbf{0} $$

$$ \Longrightarrow \mathbf{C}_{k+1}^{-1} = \{\mathbf{I}+\mathbf{C}_{k}^{-1}\mathbf{A}\}^{-1}*(-\mathbf{S}) $$

Which won't make sense since $\mathbf{S}$ is singular

  1. If I try to to find the minimal solvent, I set it up as

$$ (\mathbf{C}_{k}\mathbf{S}+\mathbf{I})*\mathbf{C}_{k+1}+\mathbf{A}=\mathbf{0} $$

$$ \Longrightarrow \mathbf{C}_{k+1}=(\mathbf{C}_{k}\mathbf{S}+\mathbf{I})^{-1}*(-\mathbf{A}) $$

But this doesn't seem to be working either.

  1. A last, non-Bernoulli iteration I set up was

$$ \mathbf{C}_{k}\mathbf{S}\mathbf{C}_{k}+\mathbf{C}_{k+1}+\mathbf{A}=\mathbf{0} $$

$$ \Longrightarrow \mathbf{C}_{k+1}=-\mathbf{A}-\mathbf{C}_{k}\mathbf{S}\mathbf{C}_{k} $$

Which seems to be working but I'm not sure which root it converges to. Also the final estimate $\mathbf{C}_{k}$ converges to, somehow appears to be twice the actual value (upon performing a ground truth test).

My queries are

1- Am I on the right track on dealing with this problem? If so, where am I making mistakes?

2- Is there any procedure to find the dominant and minimal solvent when the coefficient of the square term is singular?

3- Is the last, non-Bernoulli iteration valid? If so, why is the result twice the actual one? Which root does it converge to?

Any guidance will be highly appreciated. Thank you.

added 310 characters in body
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I have a quadratic matrix equation

CSC+C+A=0$$ \mathbf{C}\mathbf{S}\mathbf{C}+\mathbf{C}+\mathbf{A}=\mathbf{0} $$

Where C$\mathbf{C}$ is a covariance matrix (symmetric, positive semi definite), S$\mathbf{S}$ is a singular matrix and A$\mathbf{A}$ is some matrix of the form A=a*a'$\mathbf{A}=a*a^{T}$ (Product of a column vector with its transpose). I need to iteratively find C$\mathbf{C}$

  1. If I try to set up the problem using Bernoulli iteration, in order to find the dominant solvent I would have to go for

S+{I+inv(C|k|)*A}*inv(C|k+1|) = 0

=> inv(C|k+1|) = -inv[{I+inv(C|k|)*A}]*S$$ \mathbf{S}+\{\mathbf{I}+\mathbf{C}_{k}^{-1}\mathbf{S}\}*\mathbf{C}_{k+1}^{-1} = \mathbf{0} $$

=> C|k+1| = inv[-inv[{I+inv(C|k|)*A}]*S]$$ \Longrightarrow \mathbf{C}_{k+1}^{-1} = \{\mathbf{I}+\mathbf{C}_{k}^{-1}\mathbf{S}\}^{-1}*(-\mathbf{S}) $$

Which won't make sense since S$\mathbf{S}$ is singular

  1. If I try to to find the minimal solvent, I set it up as

(C|k|S+I)*C|k+1|+A = 0$$ (\mathbf{C}_{k}\mathbf{S}+\mathbf{I})*\mathbf{C}_{k+1}+\mathbf{A}=\mathbf{0} $$

=> C|k+1| = inv{C|k|S+I}*(-A)$$ \Longrightarrow \mathbf{C}_{k+1}=(\mathbf{C}_{k}\mathbf{S}+\mathbf{I})^{-1}*(-\mathbf{A}) $$

But this doesn't seem to be working as welleither.

  1. A last, non-Bernoulli iteration I set up was

C|k|SC|k|+C|k+1|+A = 0$$ \mathbf{C}_{k}\mathbf{S}\mathbf{C}_{k}+\mathbf{C}_{k+1}+\mathbf{A}=\mathbf{0} $$

=>C|k+1| = -A-C|k|SC|k|$$ \Longrightarrow \mathbf{C}_{k+1}=-\mathbf{A}-\mathbf{C}_{k}\mathbf{S}\mathbf{C}_{k} $$

Which seems to be working but I'm not sure which root it converges to. Also the final estimate C|k|$\mathbf{C}_{k}$ converges to, somehow appears to be twice the actual value (upon performing a ground truth test).

My queries are

1- Am I on the right track on dealing with this problem? If so, where am I making mistakes?

2- Is there any procedure to find the dominant and minimal solvent when the coefficient of the square term is singular?

3- Is the last, non-Bernoulli iteration valid? If so, why is the result twice the actual one? Which root does it converge to?

Any guidance will be highly appreciated. Thank you.

I have a quadratic matrix equation

CSC+C+A=0

Where C is a covariance matrix (symmetric, positive semi definite), S is a singular matrix and A is some matrix of the form A=a*a' (Product of a column vector with its transpose). I need to iteratively find C

  1. If I try to set up the problem using Bernoulli iteration, in order to find the dominant solvent I would have to go for

S+{I+inv(C|k|)*A}*inv(C|k+1|) = 0

=> inv(C|k+1|) = -inv[{I+inv(C|k|)*A}]*S

=> C|k+1| = inv[-inv[{I+inv(C|k|)*A}]*S]

Which won't make sense since S is singular

  1. If I try to to find the minimal solvent, I set it up as

(C|k|S+I)*C|k+1|+A = 0

=> C|k+1| = inv{C|k|S+I}*(-A)

But this doesn't seem to be working as well.

  1. A last, non-Bernoulli iteration I set up was

C|k|SC|k|+C|k+1|+A = 0

=>C|k+1| = -A-C|k|SC|k|

Which seems to be working but I'm not sure which root it converges to. Also the final estimate C|k| converges to, somehow appears to be twice the actual value (upon performing a ground truth test).

My queries are

1- Am I on the right track on dealing with this problem? If so, where am I making mistakes?

2- Is there any procedure to find the dominant and minimal solvent when the coefficient of the square term is singular?

3- Is the last, non-Bernoulli iteration valid? If so, why is the result twice the actual one? Which root does it converge to?

Any guidance will be highly appreciated. Thank you.

I have a quadratic matrix equation

$$ \mathbf{C}\mathbf{S}\mathbf{C}+\mathbf{C}+\mathbf{A}=\mathbf{0} $$

Where $\mathbf{C}$ is a covariance matrix (symmetric, positive semi definite), $\mathbf{S}$ is a singular matrix and $\mathbf{A}$ is some matrix of the form $\mathbf{A}=a*a^{T}$ (Product of a column vector with its transpose). I need to iteratively find $\mathbf{C}$

  1. If I try to set up the problem using Bernoulli iteration, in order to find the dominant solvent I would have to go for

$$ \mathbf{S}+\{\mathbf{I}+\mathbf{C}_{k}^{-1}\mathbf{S}\}*\mathbf{C}_{k+1}^{-1} = \mathbf{0} $$

$$ \Longrightarrow \mathbf{C}_{k+1}^{-1} = \{\mathbf{I}+\mathbf{C}_{k}^{-1}\mathbf{S}\}^{-1}*(-\mathbf{S}) $$

Which won't make sense since $\mathbf{S}$ is singular

  1. If I try to to find the minimal solvent, I set it up as

$$ (\mathbf{C}_{k}\mathbf{S}+\mathbf{I})*\mathbf{C}_{k+1}+\mathbf{A}=\mathbf{0} $$

$$ \Longrightarrow \mathbf{C}_{k+1}=(\mathbf{C}_{k}\mathbf{S}+\mathbf{I})^{-1}*(-\mathbf{A}) $$

But this doesn't seem to be working either.

  1. A last, non-Bernoulli iteration I set up was

$$ \mathbf{C}_{k}\mathbf{S}\mathbf{C}_{k}+\mathbf{C}_{k+1}+\mathbf{A}=\mathbf{0} $$

$$ \Longrightarrow \mathbf{C}_{k+1}=-\mathbf{A}-\mathbf{C}_{k}\mathbf{S}\mathbf{C}_{k} $$

Which seems to be working but I'm not sure which root it converges to. Also the final estimate $\mathbf{C}_{k}$ converges to, somehow appears to be twice the actual value (upon performing a ground truth test).

My queries are

1- Am I on the right track on dealing with this problem? If so, where am I making mistakes?

2- Is there any procedure to find the dominant and minimal solvent when the coefficient of the square term is singular?

3- Is the last, non-Bernoulli iteration valid? If so, why is the result twice the actual one? Which root does it converge to?

Any guidance will be highly appreciated. Thank you.

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