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Myshkin
Myshkin
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R.P.
R.P.
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For a totally real (resp. imaginary) biquadratic number field $K$ with quadratic sub fieldssubfields $K_1$, $K_2$ and $K_3$, is there an explicit method to determine Hasse unit index $(U_K:U_{K_1}U_{K_2}U_{K_3})$?

For a totally real (resp. imaginary) biquadratic number field $K$ with quadratic sub fields $K_1$, $K_2$ and $K_3$, is there an explicit method to determine Hasse unit index $(U_K:U_{K_1}U_{K_2}U_{K_3})$?

For a totally real (resp. imaginary) biquadratic number field $K$ with quadratic subfields $K_1$, $K_2$ and $K_3$, is there an explicit method to determine Hasse unit index $(U_K:U_{K_1}U_{K_2}U_{K_3})$?

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edit approved Jun 20, 2017 at 12:57
Majid
edit approved Jun 20, 2017 at 12:57
Majid
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For a totally real (resp. imaginary) biquadratic number field K$K$ with quadratic subfields K_1sub fields $K_1$,K_2 $K_2$ and K_3$K_3$, is there an expliciteexplicit method to determine Hasse unit index (U_K:U_{K_1}U_{K_2}U_{K_3})$(U_K:U_{K_1}U_{K_2}U_{K_3})$?

For a totally real (resp. imaginary) biquadratic number field K with quadratic subfields K_1,K_2 and K_3, is there an explicite method to determine Hasse unit index (U_K:U_{K_1}U_{K_2}U_{K_3})?

For a totally real (resp. imaginary) biquadratic number field $K$ with quadratic sub fields $K_1$, $K_2$ and $K_3$, is there an explicit method to determine Hasse unit index $(U_K:U_{K_1}U_{K_2}U_{K_3})$?

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A. Maarefparvar
A. Maarefparvar
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