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roy smith
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Let $T:X\to X$ anbe a linear operator on a Banach space $X$. We know that the spectrum of $T$ is an upper semicontinuous function of $T$ for the uniform convergence: that is, if $T_n:X\to X$ is a sequence of operators, s.t, $T_n\to T$ uniformly then, given an open set $G$ containing the spectrum of $T$, $\sigma(T)$, there must exist $k$ s.t $n>k$ implies that $\sigma (T_n)$ is contained in $G$.

I would like to know if this result remainremains valid under weaker conditions, like $T_n$ converges to $T$ in the compact parts of $X$.

I'd like to know if properties like spectral gap in the spectrum remain if we weaken the notion of
convergence.

Let $T:X\to X$ an linear operator on a Banach space $X$. We know that the spectrum of $T$ is an upper semicontinuous function of $T$ for the uniform convergence: that is, if $T_n:X\to X$ is a sequence of operators, s.t, $T_n\to T$ uniformly then, given an open set $G$ containing the spectrum of $T$, $\sigma(T)$, there must exist $k$ s.t $n>k$ implies that $\sigma (T_n)$ is contained in $G$.

I would like to know if this result remain valid under weaker conditions, like $T_n$ converges to $T$ in the compact parts of $X$.

I'd like to know if properties like spectral gap in the spectrum remain if we weaken the notion of
convergence.

Let $T:X\to X$ be a linear operator on a Banach space $X$. We know that the spectrum of $T$ is an upper semicontinuous function of $T$ for the uniform convergence: that is, if $T_n:X\to X$ is a sequence of operators, s.t, $T_n\to T$ uniformly then, given an open set $G$ containing the spectrum of $T$, $\sigma(T)$, there must exist $k$ s.t $n>k$ implies that $\sigma (T_n)$ is contained in $G$.

I would like to know if this result remains valid under weaker conditions, like $T_n$ converges to $T$ in the compact parts of $X$.

I'd like to know if properties like spectral gap in the spectrum remain if we weaken the notion of
convergence.

Hy every one!

Let $T:X\to X$ an linear operator on a Banach space $X$. We know that the spectrum of $T$ is an upper semicontinuous function of $T$ for the uniform convergence, I mean: that is, Ifif $T_n:X\to X$ is a sequence of operators, s.t, $T_n\to T$ uniformly then, given an open set $G$ containing the specrumspectrum of $T$, $\sigma(T)$, there mus existsmust exist $k$ s.t $n>k$ implies that $\sigma (T_n)$ is contained in $G$.

I would like to know if this result remain valid under weaker conditions, like, $T_n$ converges to $T$ in the compact parts of $X$.

I'd like to know if properties like spectral gap in the spectrum remainsremain if we weaken the notion of
convergence.

Hy every one!

Let $T:X\to X$ an linear operator on a Banach space $X$. We know that the spectrum of $T$ is an upper semicontinuous function of $T$ for the uniform convergence, I mean, If $T_n:X\to X$ is a sequence of operators, s.t, $T_n\to T$ uniformly then, given an open set $G$ containing the specrum of $T$, $\sigma(T)$, there mus exists $k$ s.t $n>k$ implies that $\sigma (T_n)$ is contained in $G$.

I would like to know if this result remain valid under weaker conditions, like, $T_n$ converges to $T$ in the compact parts of $X$.

I'd like to know if properties like spectral gap in the spectrum remains if we weaken the notion of
convergence.

Let $T:X\to X$ an linear operator on a Banach space $X$. We know that the spectrum of $T$ is an upper semicontinuous function of $T$ for the uniform convergence: that is, if $T_n:X\to X$ is a sequence of operators, s.t, $T_n\to T$ uniformly then, given an open set $G$ containing the spectrum of $T$, $\sigma(T)$, there must exist $k$ s.t $n>k$ implies that $\sigma (T_n)$ is contained in $G$.

I would like to know if this result remain valid under weaker conditions, like $T_n$ converges to $T$ in the compact parts of $X$.

I'd like to know if properties like spectral gap in the spectrum remain if we weaken the notion of
convergence.

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Eduardo
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Continuity of the spectrum under weaker notions of convergence

Hy every one!

Let $T:X\to X$ an linear operator on a Banach space $X$. We know that the spectrum of $T$ is an upper semicontinuous function of $T$ for the uniform convergence, I mean, If $T_n:X\to X$ is a sequence of operators, s.t, $T_n\to T$ uniformly then, given an open set $G$ containing the specrum of $T$, $\sigma(T)$, there mus exists $k$ s.t $n>k$ implies that $\sigma (T_n)$ is contained in $G$.

I would like to know if this result remain valid under weaker conditions, like, $T_n$ converges to $T$ in the compact parts of $X$.

I'd like to know if properties like spectral gap in the spectrum remains if we weaken the notion of
convergence.