Let K$K$ be a covariance matrix (it. It is positive semidefinite, it'sits diagonal elements are all 1, and it'sits off-diagonals are between -1 and 1). Let K.^2$K.^2$ be its element-wise power (Hadamard power). Can we show that maximum eigenvalue of K>=$K$ are great or equal than the maximum eigenvalue of K.^2$K.^2$? K can have both positive and negative elements.
Amir Sagiv
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