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Let $X$ be an absolutely irreducible surface over an algebraically closed or finite field $k$ of characteristic $p$. Is it true that the following conditions are equivalent?

  1. There is a purely inseparable $k$-rational dominant map $\varphi\!: X \to \mathbb{P}^2$$\varphi\!: X \dashrightarrow \mathbb{P}^2$.

  2. There is a purely inseparable $k$-rational dominant map $\psi\!: \mathbb{P}^2 \to X$$\psi\!: \mathbb{P}^2 \dashrightarrow X$, i.e., $X$ is a generalized Zariski surface.

Are degrees of $\varphi$ and $\psi$ equal?

Let $X$ be an absolutely irreducible surface over an algebraically closed or finite field $k$ of characteristic $p$. Is it true that the following conditions are equivalent?

  1. There is a purely inseparable $k$-rational dominant map $\varphi\!: X \to \mathbb{P}^2$.

  2. There is a purely inseparable $k$-rational dominant map $\psi\!: \mathbb{P}^2 \to X$, i.e., $X$ is a generalized Zariski surface.

Are degrees of $\varphi$ and $\psi$ equal?

Let $X$ be an absolutely irreducible surface over an algebraically closed or finite field $k$ of characteristic $p$. Is it true that the following conditions are equivalent?

  1. There is a purely inseparable $k$-rational dominant map $\varphi\!: X \dashrightarrow \mathbb{P}^2$.

  2. There is a purely inseparable $k$-rational dominant map $\psi\!: \mathbb{P}^2 \dashrightarrow X$, i.e., $X$ is a generalized Zariski surface.

Are degrees of $\varphi$ and $\psi$ equal?

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Purely inseparable $k$-rational dominant maps between an absolutely irreducible $k$-surface and $\mathbb{P}^2$

Let $X$ be an absolutely irreducible surface over an algebraically closed or finite field $k$ of characteristic $p$. Is it true that the following conditions are equivalent?

  1. There is a purely inseparable $k$-rational dominant map $\varphi\!: X \to \mathbb{P}^2$.

  2. There is a purely inseparable $k$-rational dominant map $\psi\!: \mathbb{P}^2 \to X$, i.e., $X$ is a generalized Zariski surface.

Are degrees of $\varphi$ and $\psi$ equal?