Let $t\in (0,1)$ and

• ${a_n}{x^n} + .... + {a_1}{x^1} - f(t) = 0$
• $f(t) $ is continuous decreasing function of $t$.
• $a_i\ge0$ for all $i$.
• $y(t)$ is positive real zero of the first equition.

Can we say that $y(t)$ is continuous decreasing function of $t$?

Let $t\in (0,1)$ and

• ${a_n}{x^n} + .... + {a_1}{x^1} + f(t) = 0$
• $f(t) $ is continuous decreasing function of $t$.
• $a_i\ge0$ for all $i$.
• $y(t)$ is positive real zero of the first equition.

Can we say that $y(t)$ is continuous decreasing function of $t$?

Let $t\in (0,1)$ and

• ${a_n}{x^n} + .... + {a_1}{x^1} - f(t) = 0$
• $f(t) $ is continuous decreasing function of $t$.
• $a_i\ge0$ for all $i$.
• $y(t)$ is zero of the first equition.

Can we say that $y(t)$ is continuous decreasing function of $t$?

Let $t\in (0,1)$ and

• ${a_n}{x^n} + .... + {a_1}{x^1} - f(t) = 0$
• $f(t) $ is continuous decreasing function of $t$.
• $a_i\ge0$ for all $i$.
• $y(t)$ is positive real zero of the first equition.

Can we say that $y(t)$ is continuous decreasing function of $t$?