Let $t\in (0,1)$ and 

 - ${a_n}{x^n} + .... + {a_1}{x^1} - f(t) = 0$
 - $f(t) $ is continuous decreasing function of $t$.
 - $a_i\ge0$ for all $i$.
 - $y(t)$ is zero of the first  equition.

Can we say that $y(t)$ is continuous **decreasing** function of $t$?