Let $t\in (0,1)$ and - ${a_n}{x^n} + .... + {a_1}{x^1} - f(t) = 0$ - $f(t) $ is continuous decreasing function of $t$. - $a_i\ge0$ for all $i$. - $y(t)$ is positive real zero of the first equition. Can we say that $y(t)$ is continuous **decreasing** function of $t$?