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Alexandre Eremenko
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I'm trying to answer this problem: Consider a real function f, bandlimited by frequency $\omega_m$$\omega$, which satisfy $$\int_{-\infty}^\infty f(x)^2dx=c.$$ (For pure mathematicians: "bandlimited" means that it Fourier transform is supported on $integral(f(x)^2dx)=c$$[-\omega,\omega]$.)

Is the first derivative of this function limited in absolute value? That is, is there an expression $A(\omega_m,c)$$A(\omega,c)$ for which $f'(x)<A(\omega_m,c)$$|f'(x)|<A(\omega,c)$ for all x?

Thank for the help!

I'm trying to answer this problem: Consider a real function f, bandlimited by frequency $\omega_m$, which satisfy $integral(f(x)^2dx)=c$

Is the first derivative of this function limited in absolute value? That is, is there an expression $A(\omega_m,c)$ for which $f'(x)<A(\omega_m,c)$ for all x?

Thank for the help!

I'm trying to answer this problem: Consider a real function f, bandlimited by frequency $\omega$, which satisfy $$\int_{-\infty}^\infty f(x)^2dx=c.$$ (For pure mathematicians: "bandlimited" means that it Fourier transform is supported on $[-\omega,\omega]$.)

Is the derivative of this function limited in absolute value? That is, is there an expression $A(\omega,c)$ for which $|f'(x)|<A(\omega,c)$ for all x?

Thank for the help!

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Ron
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Derivative of Band-limited functions

I'm trying to answer this problem: Consider a real function f, bandlimited by frequency $\omega_m$, which satisfy $integral(f(x)^2dx)=c$

Is the first derivative of this function limited in absolute value? That is, is there an expression $A(\omega_m,c)$ for which $f'(x)<A(\omega_m,c)$ for all x?

Thank for the help!