I would like to know whether there exists some continuous function $F$ satisfying the following conditions: Let $R$ be all real numbers and $Q$ be all rational numbers. Denote by $F(R)$ and $F(Q)$ the ranges of $F$ on $R$ and $Q$. Could $F$ satisfy the following conditions:

1. $F$ is a surjection ($F(R)=R$), but not an injection;

2. $F(Q)\subset Q$

3. The restriction $F: Q\to Q$ is an injection, but not a surjection.

If such $F$ exists, please give an example. If not exists, could someone give a proof? Thx a lot!

Is there a continuous function $F: R\to R$ such that $F$ is a surjection but not an injection, $F(Q)\subset Q$ and the restriction $F: Q\to Q$ is an injection, but not a surjection. Here $Q$ denotes the set of rational numbers. Thx for the reply!