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aere
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EDIT: I need to think more about the question I want to ask given comments in the answer below. Please close the thread if required. I leave it undeleted because answer is useful.

Let $V \subset H \subset V^*$ be separable Hilbert spaces with continuous and dense embeddings. Define the Hilbert space $$W(0,T) = \{u \in L^2(0,T;V) : u' \in L^2(0,T;V^*)\}$$ with inner product $$(u,v)_W = \int_0^T (u(t),v(t))_{L^2(0,T;V)} + \int_0^T (u'(t), v'(t))_{L^2(0,T;V^*)}.$$

I want to know whether the set of functions of the form $$w(t) = \sum_j \phi_j w_j, \qquad\text{where $\phi_j \in C_c^\infty(0,T)$ and $w_j \in V$}$$ are dense in $W(0,T).$

We know from Lions and Magenes that $\mathcal{D}([0,T];V) \subset W(0,T)$ is dense, so the above should hopefully be true. According to a book, the set of functions $$f(t) = \sum_j t^j w_j \quad \text{where $w_j \in V$}$$ are indeed dense in $W(0,T)$.

Does this imply the result I want? Can I approximate the $t^j$ by $C_c^\infty(0,T)$ functions or something like that? (I don't think so). Or is there another way to do this? I guess I may need to replace $C_c^\infty(0,T)$ by $C_c^\infty[0,T]$..

I posted this at math.stackexchange.com but got no answers.

Let $V \subset H \subset V^*$ be separable Hilbert spaces with continuous and dense embeddings. Define the Hilbert space $$W(0,T) = \{u \in L^2(0,T;V) : u' \in L^2(0,T;V^*)\}$$ with inner product $$(u,v)_W = \int_0^T (u(t),v(t))_{L^2(0,T;V)} + \int_0^T (u'(t), v'(t))_{L^2(0,T;V^*)}.$$

I want to know whether the set of functions of the form $$w(t) = \sum_j \phi_j w_j, \qquad\text{where $\phi_j \in C_c^\infty(0,T)$ and $w_j \in V$}$$ are dense in $W(0,T).$

We know from Lions and Magenes that $\mathcal{D}([0,T];V) \subset W(0,T)$ is dense, so the above should hopefully be true. According to a book, the set of functions $$f(t) = \sum_j t^j w_j \quad \text{where $w_j \in V$}$$ are indeed dense in $W(0,T)$.

Does this imply the result I want? Can I approximate the $t^j$ by $C_c^\infty(0,T)$ functions or something like that? (I don't think so). Or is there another way to do this? I guess I may need to replace $C_c^\infty(0,T)$ by $C_c^\infty[0,T]$..

I posted this at math.stackexchange.com but got no answers.

EDIT: I need to think more about the question I want to ask given comments in the answer below. Please close the thread if required. I leave it undeleted because answer is useful.

Let $V \subset H \subset V^*$ be separable Hilbert spaces with continuous and dense embeddings. Define the Hilbert space $$W(0,T) = \{u \in L^2(0,T;V) : u' \in L^2(0,T;V^*)\}$$ with inner product $$(u,v)_W = \int_0^T (u(t),v(t))_{L^2(0,T;V)} + \int_0^T (u'(t), v'(t))_{L^2(0,T;V^*)}.$$

I want to know whether the set of functions of the form $$w(t) = \sum_j \phi_j w_j, \qquad\text{where $\phi_j \in C_c^\infty(0,T)$ and $w_j \in V$}$$ are dense in $W(0,T).$

We know from Lions and Magenes that $\mathcal{D}([0,T];V) \subset W(0,T)$ is dense, so the above should hopefully be true. According to a book, the set of functions $$f(t) = \sum_j t^j w_j \quad \text{where $w_j \in V$}$$ are indeed dense in $W(0,T)$.

Does this imply the result I want? Can I approximate the $t^j$ by $C_c^\infty(0,T)$ functions or something like that? (I don't think so). Or is there another way to do this? I guess I may need to replace $C_c^\infty(0,T)$ by $C_c^\infty[0,T]$..

I posted this at math.stackexchange.com but got no answers.

added 89 characters in body
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aere
  • 11
  • 2

Let $V \subset H \subset V^*$ be separable Hilbert spaces with continuous and dense embeddings. Define the Hilbert space $$W(0,T) = \{u \in L^2(0,T;V) : u' \in L^2(0,T;V^*)\}$$ with inner product $$(u,v)_W = \int_0^T (u(t),v(t))_{L^2(0,T;V)} + \int_0^T (u'(t), v'(t))_{L^2(0,T;V^*)}.$$

I want to know whether the set of functions of the form $$w(t) = \sum_j \phi_j w_j, \qquad\text{where $\phi_j \in C_c^\infty(0,T)$ and $w_j \in V$}$$ are dense in $W(0,T).$

We know from Lions and Magenes that $C_c^\infty(0,T;V) \subset W(0,T)$$\mathcal{D}([0,T];V) \subset W(0,T)$ is dense, so the above should hopefully be true. According to a book, the set of functions $$f(t) = \sum_j t^j w_j \quad \text{where $w_j \in V$}$$ are indeed dense in $W(0,T)$.

Does this imply the result I want? Can I approximate the $t^j$ by $C_c^\infty(0,T)$ functions or something like that? (I don't think so). Or is there another way to do this? ThanksI guess I may need to replace $C_c^\infty(0,T)$ by $C_c^\infty[0,T]$..

I posted this at math.stackexchange.com but got no answers.

Let $V \subset H \subset V^*$ be separable Hilbert spaces with continuous and dense embeddings. Define the Hilbert space $$W(0,T) = \{u \in L^2(0,T;V) : u' \in L^2(0,T;V^*)\}$$ with inner product $$(u,v)_W = \int_0^T (u(t),v(t))_{L^2(0,T;V)} + \int_0^T (u'(t), v'(t))_{L^2(0,T;V^*)}.$$

I want to know whether the set of functions of the form $$w(t) = \sum_j \phi_j w_j, \qquad\text{where $\phi_j \in C_c^\infty(0,T)$ and $w_j \in V$}$$ are dense in $W(0,T).$

We know that $C_c^\infty(0,T;V) \subset W(0,T)$ is dense, so the above should hopefully be true. According to a book, the set of functions $$f(t) = \sum_j t^j w_j \quad \text{where $w_j \in V$}$$ are indeed dense in $W(0,T)$.

Does this imply the result I want? Can I approximate the $t^j$ by $C_c^\infty(0,T)$ functions or something like that? (I don't think so). Or is there another way to do this? Thanks.

I posted this at math.stackexchange.com but got no answers.

Let $V \subset H \subset V^*$ be separable Hilbert spaces with continuous and dense embeddings. Define the Hilbert space $$W(0,T) = \{u \in L^2(0,T;V) : u' \in L^2(0,T;V^*)\}$$ with inner product $$(u,v)_W = \int_0^T (u(t),v(t))_{L^2(0,T;V)} + \int_0^T (u'(t), v'(t))_{L^2(0,T;V^*)}.$$

I want to know whether the set of functions of the form $$w(t) = \sum_j \phi_j w_j, \qquad\text{where $\phi_j \in C_c^\infty(0,T)$ and $w_j \in V$}$$ are dense in $W(0,T).$

We know from Lions and Magenes that $\mathcal{D}([0,T];V) \subset W(0,T)$ is dense, so the above should hopefully be true. According to a book, the set of functions $$f(t) = \sum_j t^j w_j \quad \text{where $w_j \in V$}$$ are indeed dense in $W(0,T)$.

Does this imply the result I want? Can I approximate the $t^j$ by $C_c^\infty(0,T)$ functions or something like that? (I don't think so). Or is there another way to do this? I guess I may need to replace $C_c^\infty(0,T)$ by $C_c^\infty[0,T]$..

I posted this at math.stackexchange.com but got no answers.

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aere
  • 11
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Density of certain functions in $C_c^\infty(0,T;V)$ in the space $W(0,T) \approx H^1(0,T;V)$?

Let $V \subset H \subset V^*$ be separable Hilbert spaces with continuous and dense embeddings. Define the Hilbert space $$W(0,T) = \{u \in L^2(0,T;V) : u' \in L^2(0,T;V^*)\}$$ with inner product $$(u,v)_W = \int_0^T (u(t),v(t))_{L^2(0,T;V)} + \int_0^T (u'(t), v'(t))_{L^2(0,T;V^*)}.$$

I want to know whether the set of functions of the form $$w(t) = \sum_j \phi_j w_j, \qquad\text{where $\phi_j \in C_c^\infty(0,T)$ and $w_j \in V$}$$ are dense in $W(0,T).$

We know that $C_c^\infty(0,T;V) \subset W(0,T)$ is dense, so the above should hopefully be true. According to a book, the set of functions $$f(t) = \sum_j t^j w_j \quad \text{where $w_j \in V$}$$ are indeed dense in $W(0,T)$.

Does this imply the result I want? Can I approximate the $t^j$ by $C_c^\infty(0,T)$ functions or something like that? (I don't think so). Or is there another way to do this? Thanks.

I posted this at math.stackexchange.com but got no answers.