Let $A=\{\sqrt{2}\sin(\sqrt{n^2+a}\pi x)\} _{n=1}^\infty$$A=\{\sqrt{2}\sin(\sqrt{n^2+a} \pi x)\} _{n=1}^\infty$, where $a$ is a positive real number. Is $A$ a Riesz Basis of $L^2(0,\pi)$$L^2(0,1)$?
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