The following is an equation describing the coupled phases of N oscillators according to the Kuramoto model:
$ 1 = K \int_{-\pi/2}^{\pi/2}cos^2(\theta)g(KRsin(\theta))d\theta$$$ 1 = K \int_{-\pi/2}^{\pi/2}\cos^{2}\left(\theta\right)\, {\rm g}\left(KR\sin\left(\theta\right)\right)\,{\rm d}\theta $$
We assume that g is a symmetric distribution with zero mean, since the equation is written from the point of view of a reference frame rotating together with the oscillator.
I need to take the $\lim_{R \rightarrow0^+}$ to solve for the coupling strength Kc. This can't be solved with Wolfram Alpha since g is not read as a gaussian distribution but instead as a constant.
How else can you solve this limit?