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user95750
  • Member for 8 years, 4 months
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 Commentator
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Number of subgroups of a group of orders $p^3$
@YCor, Yes because it is answered.
comment
Number of subgroups of a group of orders $p^3$
@YCor, Thanks, yes it is easy ... I tried to remove the question but it doesn't work.
accepted
Number of subgroups of a group of orders $p^3$
comment
Number of subgroups of a group of orders $p^3$
The link doesn't work with me : The requested URL /~boij/kandexjobbVT11/Material/pgroups.pdf. was not found on this server.
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Number of subgroups of a group of orders $p^3$
Why the downvote?
asked
Number of subgroups of a group of orders $p^3$
comment
Estimate the ratio $\dfrac{\left(\sum_{n\le X}a(n)\right)^2}{\underset{n\le X}{\sum} a(n)^2}$
@GHfromMO, That's very helpful thank you very much.
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Estimate the ratio $\dfrac{\left(\sum_{n\le X}a(n)\right)^2}{\underset{n\le X}{\sum} a(n)^2}$
Could you suggest to me some references in which I can find tools to prove that $$X\ll\dfrac{\left(\sum_{n\le X}a(n)\right)^2}{\underset{n\le X}{\sum} a(n)^2}$$ for Eisenstein series. Many thanks.
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 Supporter
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 Scholar
accepted
Estimate the ratio $\dfrac{\left(\sum_{n\le X}a(n)\right)^2}{\underset{n\le X}{\sum} a(n)^2}$
revised
Estimate the ratio $\dfrac{\left(\sum_{n\le X}a(n)\right)^2}{\underset{n\le X}{\sum} a(n)^2}$
deleted 47 characters in body
comment
Estimate the ratio $\dfrac{\left(\sum_{n\le X}a(n)\right)^2}{\underset{n\le X}{\sum} a(n)^2}$
@GHfromMO, Thank you very much for the reference.
comment
Estimate the ratio $\dfrac{\left(\sum_{n\le X}a(n)\right)^2}{\underset{n\le X}{\sum} a(n)^2}$
Thanks for your answer, I am interested to the general case $f\in M_{k+1/2}(\Gamma_0(4N),\chi)$
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 Editor
revised
Estimate the ratio $\dfrac{\left(\sum_{n\le X}a(n)\right)^2}{\underset{n\le X}{\sum} a(n)^2}$
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 Student
asked
Estimate the ratio $\dfrac{\left(\sum_{n\le X}a(n)\right)^2}{\underset{n\le X}{\sum} a(n)^2}$
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 Autobiographer
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