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Justin Noel's user avatar
Justin Noel's user avatar
Justin Noel's user avatar
Justin Noel
  • Member for 14 years, 3 months
  • Last seen more than 3 years ago
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Strong Convergence vs Conditional Convergence for Spectral Sequences (Is there a simple explanation?)
Unless I'm missing something, as long as for each target group H_k, the part of the spectral sequence calculating E_\infty H_k, has no differentials in or out after the nth page (which can depend on k) then the spectral sequence will strongly converge under these conditions.
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Strong Convergence vs Conditional Convergence for Spectral Sequences (Is there a simple explanation?)
I second Drew's recommendation. The paper is complex, but wonderful. The key ingredients are: A spectral sequence should be associated to a good filtration: the intersection/union of the filtration that should be 0 is very much 0 and conditional convergence gives this by definition. You should also be sure that the respective union/intersection of your filtration actually calculates what you are looking for. In practice, checking these conditions is easy. Under these conditions the only thing to check is that
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When do colimits agree with homotopy colimits?
Hi Greg, perhaps you mean $X^H$ is contractible for all non-trivial subgroups $H\subset G$ ($G_+$ is cofibrant, but is not contractible for all proper subgroups unless $G$ is trivial).
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$RO(G)$-graded homotopy groups vs. Mackey functors
Expanded argument to clarify dependence on rationals.
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$RO(G)$-graded homotopy groups vs. Mackey functors
@AaronMazel-Gee: Sorry, that was less than clear because I rushed the answer. I filled out the answer a bit more. Hopefully, it is more understandable now.
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$RO(G)$-graded homotopy groups vs. Mackey functors
Added a couple paragraphs of clarifying information and additional information for equivariant $K$-theory.
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$RO(G)$-graded homotopy groups vs. Mackey functors
Added a couple paragraphs of clarifying information and additional information for equivariant $K$-theory.
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$RO(G)$-graded homotopy groups vs. Mackey functors
Need suspensions to get that C_f is closed under suspension.
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