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I am sorry for this mistake. I consider that the Schur Multiplier is equal to 2. And for the second group in the above discussion we have $G\cong S_3\times {\rm PSL}(2,q)$, is this true?
Many Thanks for the helps. Excuse me you mean that we conclude that $G\cong {\Bbb Z_3}\times {\rm PGL}(2,q)$ and one more which is a subdirect product of $S_3$ and ${\rm PSL}(2,q)$?