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Destiny freedom
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If $\binom{2p}{p}$ is $(-1)^{p-1} \bmod 2p+1$ is then $2p+1$ prime?
for $p=1093^2$,I found can by hand ,Note $1093^2|2^{1092}-1$,so $(2\cdot 1093^2+1)|(\binom{2\cdot 1093^2}{1093^2}+1$
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If $\binom{2p}{p}$ is $(-1)^{p-1} \bmod 2p+1$ is then $2p+1$ prime?
can you prove $(2953\times 2+1)|\binom{2\cdot 2953}{2953}+1$ by hand?
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