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Piero D'Ancona's user avatar
Piero D'Ancona's user avatar
Piero D'Ancona
  • Member for 14 years, 5 months
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Sufficient conditions for boundedness of Fourier transform
Of course, distributions are ok since I can regularize them
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Sufficient conditions for boundedness of Fourier transform
@Guido: you are right, but such objects are not functions, rather homogeneous distributions, since they are not locally integrable. In dim 1 you get vp(1/x), the principal value. The example I mentioned is essentially the next best thing: think of $\frac{x}{x^2+\epsilon^2}$
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Sufficient conditions for boundedness of Fourier transform
@Alexander: I am using the standard extension by Schwartz to tempered distributions
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If $f \in L^p(\Omega)$, then $f \in L^q(\Omega)$ for some $q < p + \epsilon$?
Let me add that functions satisfying self-improvement properties like the one considered here are rather important in harmonic analysis (I am thinking of reverse Hölder classes)
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Show that the kernel $|x -y|^{-1}$ on $\mathbb{R}^3 \times \mathbb{R}^3$ is Hilbert Schmidt with respect to a weighted $L^2$ space
The first case works also if $(1+|y|)^\beta$ is replaced by $|y|^\beta$ for $\beta<n$
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What is dispersive estimate?
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Huygens' trigonometric inequality
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Hardy inequality
Of course, the $L^{q,2}$ norm is controlled by the $L^2$ norm of $\partial u$. This is a Sobolev embedding with values in Lorentz spaces
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