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PhoemueX
  • Member for 10 years, 2 months
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  • Germany
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For what LCH groups is the Haar measure $\mu(U x U)$ bounded?
@YCor: I cannot tell you much about the meaning related to the geometry/properties of the group. I got interested in this question through certain properties of so-called (two-sided) Wiener Amalgam spaces, where the norm of $f$ is essentially the $L^1$ norm of the maximal function $M f(x) = \| f\|_{L^\infty (QxQ)}$. I then wanted to understand the norm of $1_{x Q}$, in particular compared to the norm in the one-sided Amalgam spaces.
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For what LCH groups is the Haar measure $\mu(U x U)$ bounded?
This is really incredible! Thanks! I still need to check the fine print and understand parts of the intuitive explanations that you provide, but I could follow the main argument. One thing you did not stress: the uniqueness statement of the Riesz projection theorem is what allows to deduce the conjugation invariance, right?
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For what LCH groups is the Haar measure $\mu(U x U)$ bounded?
@ მამუკა ჯიბლაძე: The Heisenberg group is such an example. I can add the details later today if you are interested.
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Is there a function that is not absolutely integrable in [−π,π] so that its Fourier Series Exists?
The OP is working on the torus $[-\pi,\pi]$, not on the whole real line.
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Completeness of exponentials $\mathcal{E} = \{ e^{ist} : s \in \mathbb{R} \}$ in $L^p(\mu)$
@LksRheil: If you are interested in the Fourier-analytic part, one reference is "Probability theory" by Bauer. I only have the German version right now, but there the precise statement you want is Theorem 23.4.
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Extension of universal approximation theorem
On $C_1(I_d)$, you are still using the uniform norm?
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