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Isn't "$V^{\mathbb{B}}\models$ the Riemann hypothesis holds" such a statement? Or are you looking for some "functional analytic" statement about the space $C^+(St(\mathbb{B}))$?
Am I right that $\mathbb{R}$ can't be a nontrivial ultraproduct over any index set? If the ultrafilter $U$ is countably incomplete then the result is $\aleph_1$-saturated, hence not $\mathbb{R}$. If it's countably complete then it's $\kappa$-complete for some measurable cardinal $\kappa$. If measure one many fields are non-Archimedean then so is the ultraproduct. If measure one many are Archimedean then they are subfields of $\mathbb{R}$, so by $(2^\mathfrak{c})^+$-completeness the ultraproduct is trivial.
This seems to work, but you need to explain: why does a branch that extends $\sigma$ and has supremum $q+\sup\sigma$ exist for each $q$? I think that's the purpose of choosing those $\omega$-sequences. See also Theorem III.5.12 of Kunen or Theorem 9.16 of Jech. They (as well as Roitman, and your proposed construction) are all essentially the same, up to minor notational variations