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martyall's user avatar
martyall's user avatar
martyall
  • Member for 10 years, 9 months
  • Last seen more than a month ago
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Why is this frobenius acting like that frobenius?
im speaking more to the fact that the frobenius already has an action on H^{1}(U), and here i could define another. it's not obvious to me that they are the same.
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