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Angelo
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Mathematically mature way to think about Mayer–Vietoris
Thanks. I don't know about talented; it's just that I have been around for a fairly long time.
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Mathematically mature way to think about Mayer–Vietoris
The cohomology of $j! \mathbb{Z}$ is not the cohomology of the open subset. If $X$ is compact, it is the cohomology with compact support; in this way you can get Mayer-Vietoris for Borel-Moore homology.
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Mathematically mature way to think about Mayer–Vietoris
This works for finite closed covers, not for open covers.
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scheme-theoretic description of abelian schemes
Metha and Srinivas wrote a paper on this topic, "Varieties in positive characteristic with trivial tangent bundle", <archive.numdam.org/ARCHIVE/CM/CM_1987__64_2/CM_1987__64_2_1‌​91_0/…>.
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Natural embedding GL_n(C) -> C^{n^2} \ {0} induces zero on cohomology
Yes, for $n=1$ the two spaces coincide. Let me add that the reason why $\mathrm H^{2n^2-1}(GL_n(\mathbb C)) = 0$ is that $GL_n(\mathbb C)$ is homotopy equivalent to the unitary group $U_n$, which has dimension $n^2$. Or, $\mathrm H^{i}(GL_n(\mathbb C)) = 0$ for $i > n^2$ because $GL_n(\mathbb C)$ is an affine variety of dimension $n^2$.
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Extra automorphisms of curves and definability over \bar Q
Another equivalent condition, which is sometimes useful, is that there are no non-zero quadratic differential that are invariant for the action of the automorphism group.
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scheme-theoretic description of abelian schemes
By a transitive action I mean that the morphism $\underline{\rm Aut}_S X \to X$ coming from the section is scheme-theoretically surjective. Since the fibers are connected, this implies that the connected component of the identity must dominate each fiber, and this is enough to conclude.
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Are extensions of linear groups linear?
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