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saurav
  • Member for 14 years, 9 months
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morphism of schemes that is closed at topological space level
But $f(E_c)[=f(E\cap X_c)]$ may not be equal to $f(E)_c[=f(E)\cap Y_c]$. To say that $f(E_c)$ is closed in $Y_c$, we probably need this equality.
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