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Ali Taghavi's user avatar
Ali Taghavi's user avatar
Ali Taghavi
  • Member for 11 years, 5 months
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Coupled Riccati equations
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On which subspace $W\subset C^{\infty}[0,1]$ is $(Df)(x)=xf'(x)$ a bounded operator provided all functions in $W$ are flat functions?
Thank you and my (prevciously) +1. BTW "Entire function of ln(x)" This remind me of the concept of "Dulac series" in the investigation of the finteness part of the Hilbert 16th problem
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Every closed surface divides a closed 3-manifold $X$ into two parts if and only if $H_1(X)$ is finite
@mme I remember a similar phrase in Hirsch diff topology : ebery codimension one compact summanfiold of a compact manifold separate the space provided all thing are orientable
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A possible invariant associated to a compact group
I dont know if this invariant is well defined and helpful or no?
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A possible invariant associated to a compact group
@HJRW Thank you very much for your attention to my question. Yes, as you wrote, $n$ is allowed to depend on $G$. For finite group $G$ we have an effective action of $G$ on $\mathbb{R}^{|G|}$ since $G$ is embedded in $S_{|G|}$. So, according to the update version of the question, I think we may define the following invariant associated to group: The minimum of all $n$ for which there exists an effective action of $G$ on $\mathbb{R}^n$ such that the space of $G$ fixed vector is a one dimensional space. Some how similar to irreducible representation.
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A possible invariant associated to a compact group
@YCor I think "Sym" is more popular since the notation $S_n$ used for symmetric group but every element of $S_n$ is called a permutation.
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A possible invariant associated to a compact group
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Proposals for polymath projects
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Condensed Pontryagin duality
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A possible invariant associated to a compact group
@Echo Ok in this sense only very huge groups does not admit injective morphisms $G\to Per(|mathbb{R}^n}$
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A possible invariant associated to a compact group
@Echo thank you for your comment. But in the question we requiere that action is by isometry not exclusively by permutation. In the example we have permutation but in general we work with isometry. I think the answer of Prof. Valette completes the answer to this question since it explicitly represent the quadratic form
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A possible invariant associated to a compact group
@AlainValette Thank you very much for your very helpful answer
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