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user33845
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Proof that the Hodge-de Rham Rank Equals the Euler Characteristic
P.S. By index of an operator $A$ I mean dim of the image of $A$ minus the dim of the cokernel of $A$.
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Proof that the Hodge-de Rham Rank Equals the Euler Characteristic
. . . so how does one get from the Hodge decomposition to index equaling the Euler characteristic?
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Proof that the Hodge-de Rham Rank Equals the Euler Characteristic