Skip to main content
Dinesh's user avatar
Dinesh's user avatar
Dinesh's user avatar
Dinesh
  • Member for 11 years, 11 months
  • Last seen more than 5 years ago
awarded
accepted
awarded
comment
Continuity of a Functional
So, basically, $M$ can be considered as having support $[\alpha,1-\alpha],\alpha>0$
revised
Continuity of a Functional
added 25 characters in body
Loading…
comment
Continuity of a Functional
@MartinHairer, thank you very much for your remark. That was a mistake, sorry. I am in fact looking at the integral to $T_{sup}(F)=\sup_{\{M\in\frak{M}\}}\{\int_{[\alpha,1-\alpha]}F^{-1}(s)M(ds)\}$ for $\alpha>0$
revised
Continuity of a Functional
added 126 characters in body
Loading…
revised
Continuity of a Functional
deleted 84 characters in body
Loading…
comment
Continuity of a Functional
@MartinHairer, yes, sorry. I mean CDF. And, also, yes, weak convergence.
comment
Continuity of a Functional
@JochenWengenroth, Sorry, I avoided details as I thought the details might not effect the result. I have added details if that can help.
awarded
revised
Loading…
asked
Loading…