Skip to main content
adam W's user avatar
adam W's user avatar
adam W's user avatar
adam W
  • Member for 12 years, 2 months
  • Last seen more than 1 year ago
comment
Sherman-Morrison type formula for Moore-Penrose pseudoinverse
@trenta3 one post of mine that talks about psuedo inverse and span: math.stackexchange.com/a/317053/43193, just look for the section proof
comment
Sherman-Morrison type formula for Moore-Penrose pseudoinverse
@trenta3 I remember I might have some perinent posts on my math.stackexchange. I haven't posted too terribly much so it may be of use to you to look. Otherwise, if I think of what I was talking about here, I may be able to explain better later. no source-- I think I was doing it on my own really
awarded
comment
Is this a new formula? $\Delta^d x^n/d! = \sum_k \left[ x \atop k\right]{ k+n \brace x + d}(-1)^{x+k}$
I only just realized that maybe it is ok to go all the way and take the single term $0^{\underline{0}}=1$ which would then give the formula for $d=0$. It is just a weird concept to consider taking a factor of $1$ out and leaving $0$ behind.
comment
Is this a new formula? $\Delta^d x^n/d! = \sum_k \left[ x \atop k\right]{ k+n \brace x + d}(-1)^{x+k}$
I thought as much myself, but have not seen it in that book. Note that this formula actually eradicates the power on $x$, as opposed to just changing the basis, even when not applying any difference.
awarded
Loading…
comment
Sherman-Morrison type formula for Moore-Penrose pseudoinverse
If $\mathbf A$ is symmetric and so is the update to it, then I get that the Sherman-Morrison formula works as is (replacing inverse with pseudo-inverse of course). Otherwise, if I am correct, the formula gives you only a general inverse, and correction using the null space is required to make it the desired pseudo-inverse.
awarded