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A graded ring $R$ is graded-local iff $R_0$ is a local ring?
@JohanÖinert The answer to your question is yes.
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vanishing of local cohomology $H^2_{(x,y)}\left(\frac{\Bbb Z[x,y]}{(5x+4y)}\right)=0$
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Question on bigraded module.
I think this question was posed on SE not too long ago. I remember that I answered this but I can't find it right now.
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vanishing of local cohomology $H^2_{(x,y)}\left(\frac{\Bbb Z[x,y]}{(5x+4y)}\right)=0$
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vanishing of local cohomology $H^2_{(x,y)}\left(\frac{\Bbb Z[x,y]}{(5x+4y)}\right)=0$
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vanishing of local cohomology $H^2_{(x,y)}\left(\frac{\Bbb Z[x,y]}{(5x+4y)}\right)=0$
I don't know what are you talking about, but what I said referred to you comment, that is, $H_{(x,y)}^2(\mathbb Z[x,y])=0$ implies, by localizing to $Z−\{0\}$, that the similar local cohomology over $\mathbb Q$ is $0$ and this is false!
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Is a polynomial ring integral over this subring ?
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Homogeneous ideal and its system of generators
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transcendence degree of subring of polynomial ring
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Homogeneous ideal and its system of generators
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