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Given integer n and k, split the set {x| - 2^n + 1 ≤ x ≤ 2^n} into two subsets A and B, so that |A| = |B| and $\sum_{a\in A}a^k=\sum_{b\in B}b^k$

Feb 22, 2021

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Given integer n and k, split the set {x| - 2^n + 1 ≤ x ≤ 2^n} into two subsets A and B, so that |A| = |B| and $\sum_{a\in A}a^k=\sum_{b\in B}b^k$

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