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user16456
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Can a sequence of polynomials in a translation invariant linear space pointwise converge to a polynomial which is not included in that space? In one variable this is impossible.
Coefficients are linear combinations of derivatives, derivatives are linear combinations of differences, differences are linear combinations of function values - hence point-wise convergence does imply coefficient-wise convergence.
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Descending chain of translation invariant linear spaces of polynomials
"An infinite descending chain $T_{\alpha}$ would give an infinite ascending chain $I(T_{\alpha})$..." This is true only if $T_1\ne T_2$ implies that the closure of $T_1$ is different from the closure of $T_2$.If $T_1$ and $T_2$ have the same closure, then $I(T_1)$ and $I(T_2)$ are the same.
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Descending chain of translation invariant linear spaces of polynomials
A linear space of polynomials is translation invariant if and only if it is invariant under partial differentiation.
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Can a sequence of polynomials in a translation invariant linear space pointwise converge to a polynomial which is not included in that space? In one variable this is impossible.
A sequence of polynomials converges point-wise to a polynomial if and only if it converges coefficient-wise to it. A linear space of polynomials is translation invariant if and only if it is invariant under partial differentiation.
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Examples of amenable groups other than finite groups
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