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gdavtor
  • Member for 5 years, 9 months
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Is the Legendre transform as an operator Lipschitz?
Lipschitz constant of 1 would then imply that LF is an isometry (on $C_{lsc}(\mathbb{R}^n)$), by the involution property $f^{**} = f$? This makes sense geometrically actually now that I think about it. Thank you!
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