User Luke Diahan

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comment

Thank you for your comment. All we need further is that $\Omega$ is connected so the definition makes sense.

Jul 19, 2018 at 11:36

comment

You mean that these are true for any open, bounded domain $\Omega$ in $\mathbb{C}^{n}$ without any assumption on the smoothness of its boundary.

Jul 19, 2018 at 1:21

awarded

Student

Jul 18, 2018 at 14:05

awarded

Editor

Jul 18, 2018 at 13:50

revised

edited title

Jul 18, 2018 at 13:49

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asked

Jul 18, 2018 at 13:41

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