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Ye Changqing's user avatar
Ye Changqing's user avatar
Ye Changqing's user avatar
Ye Changqing
  • Member for 7 years, 3 months
  • Last seen more than 6 years ago
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Is there a criterion for compactness in $L^\infty(\Omega)$ with strong topology?
Thanks again, but how to construct a bi-measurable function which takes null sets to null sets?
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Is there a criterion for compactness in $L^\infty(\Omega)$ with strong topology?
Thanks, but why all $L^\infty(\Omega)$ are isomorphic? if $\Omega_1$ and $\Omega_2$ are topologically isomorphic, the isomorphism between $L^\infty(\Omega_1)$ and $L^\infty(\Omega_2)$ is trivial. P.s. the criterion in Dunford and Schwartz's book seems very hard to apply, sad...
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