Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.
Thank you! Just checking, in your paper, you work with homogenous cochains, so a 2-cocycle would have 3 arguments instead of 2; does this change the formula?
@MikhailBorovoi Thanks for your comments, they are very helpful. Do you have a reference for this formula? One subtle feature is that Magma views $G$-modules as acting on the right (as opposed to the traditional action on the left), so this might affect the formula.
One thing to note is that if $X$ is normal and (geometrically) irreducible, then the codimension of $Y$ in $X$ must be $1$. Indeed, if the codimension of $Y$ is at least $2$, then the restriction map $k = \mathcal{O}(X)\rightarrow \mathcal{O}(U)$ is an isomorphism, so $U$ cannot be affine.
This would require knowing that the `generic fiber' homomorphism $\text{CH}^p(X)\rightarrow \text{CH}^p(X_K)$ is surjective when restricted to the subgroups of algebraically trivial cycle classes. I don't see an obvious reason why that's true, nor what the definition of such a subgroup of $\text{CH}^p(X)$ would actually be. (Fulton only considers algebraic triviality for varieties over a field.)
I'm a bit confused about the sentence ' for any rational point s in S(Q), the pullback of AJ(Z) over s should match the usual AJ map in the absolute setting'. How it the pullback of an element of $H^1(\Gamma, R^{2d-1}\pi_*(\mathbb{Q}_l)^H)$ naturally an element of $H^1(G_{\mathbb{Q}}, H^{2d-1}(\bar{X},\mathbb{Q}_l))$? Also what do you mean by $Z\rightarrow S'$ having connected fibres? Each closed subscheme in the support of $Z$ has connected fibres?
@JasonStarr if you have any thoughts on my followup question I would be very grateful if you would like to share them: mathoverflow.net/questions/462776/…