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Martin Modrák's user avatar
Martin Modrák's user avatar
Martin Modrák
  • Member for 7 years, 9 months
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Handling absolute value and other discontinuities in numerical optimization methods that use gradients
It might be that good guess here means that you start in an attraction basin where there are no discontinuities in the derivative between the initial location and the optimum. In such a case, the algorithm may never see the discontinuity and just work fine.
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Dispersion of random walk with scaled step sizes
You are right, I forgot to take into account the correlations induced by using $X_{j-1}$ as an argument to $\sigma$. Indeed, I can choose $\sigma$ such that the inequality does not hold.
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Dispersion of random walk with scaled step sizes
Maybe I am missing somehitng basic, but since $\sigma$ only ever takes values in $[1,2]$, it seems easy to show that $\mathbb{P}( X_N \in [-1,1]) \leq \mathbb{P}( S_N \in [-1,1])$ where $S_N = \sum_{j=1}^N Y_j$. And since $S_N \sim N(0, \sqrt{N})$, the inequality seems trivial. Or did I misunderstand the question?
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Convergence rate of the sum of squares of inverse distances of random points which become dense in a region
$D_n$ is not well-defined as written as whenever $i = j$ you have zero in the denominator. Maybe you wanted to sum only over $i < j$?
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Stopping time on the sum of a moving window
The details are a bit over my head, but the more I read it, the more it seems to me that your case satisfies the assumptions laid out (e.g. you have a transient process) and the balayage and potential operators for your process should be at least somewhat nice.
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Stopping time on the sum of a moving window
You can translate to a multidimensional state that depends only on the previous time, i.e. $\bar{S}_{(k)}$ r.v. over $\mathbb{R}^N$ with the transition probability $P(\bar{S}_{(k + 1)} = (a_1, ..., a_N) | \bar{S}_{(k)} = (b_1, ..., b_N)) = P(\xi_{k + N + 1} = a_1)$ when $a_2 = b_1, a_3 = b_2, ..., a_N = b_{N - 1}$ and 0 otherwise. Then - following the intro in Baxter & Chacon (link above) - you need to transform your stopping criterion into a "balayage" $\mu \to \nu$ and determine the potential operator $G$ for this process and you get your expected stopping time as $\int (\mu - \nu) dG$.
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Stopping time on the sum of a moving window
OK, one more stab - you can translate $S_{(k)}$ into an $N$-state Markov chain (continuous state, discrete time). There appears to be a strong theory on stopping times for Markov chains (that I admit to not really understanding), e.g.: doi.org/10.1215/ijm/1256049786
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Stopping time on the sum of a moving window
Isn't $S_{(k)}$ just a random walk? Specifically, you have $S_{(k + 1)} - S_{(k)} = \xi_{k + N + 1} - \xi_{k}$? This should then let you use all the theory of random walks directly...
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Sharp approximation to expectation of a ratio of a Gaussian vector
Just one more idea, barely fleshed out - it seems that if you can bound $p_i$ from below, you can obtain a polynomial approximating $\left(1 + u \left(\frac{1}{p_i} - 1 \right)\right)^{-\frac{1}{2}}$ with constant error. Substituting that polynomial into the final integral in my answer results in nasty but apparently analytically tractable integrals, which than has constant error...
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Sharp approximation to expectation of a ratio of a Gaussian vector
Just letting you now that I have substantially corrected and expanded my answer - although I wasn't able to get full solution, I think I came close, maybe you can make the next step. I am done with editing for the foreseeable future.
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Sharp approximation to expectation of a ratio of a Gaussian vector
Added the joint PDF and solution for n = 2
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