20
votes
Accepted
Is there a universal property characterizing the category of compact Hausdorff spaces?
I definitely expect that there is much more than one good answer. But, here is one that one can get easily by just patching together several classical facts:
The category of compact Hausdorf ...
15
votes
Is there a universal property characterizing the category of compact Hausdorff spaces?
As has already been remarked, $\mathbf{CHaus}$ is monadic over $\mathbf{Set}$.
It is also a pretopos, meaning roughly that it has the finitary properties of
$\mathbf{Set}$.
Another more symmetrical ...
8
votes
Is there a universal property characterizing the category of compact Hausdorff spaces?
We can describe $\mathbf{CHaus}$ with a universal property inside the $2$-category of all cocomplete categories and cocontinuous functors. Namely, $\mathbf{CHaus}$ is the universal cocomplete category ...
6
votes
Accepted
What does overtness mean for metric spaces?
David Roberts has rubbed the magic lamp and the genie appears!
Even though the notion of overtness does depend on the strength of the ambient logic,
I believe the question here is with the notion of ...
5
votes
What does overtness mean for metric spaces?
The spectrum of a commutative ring, defined as the classifying locale of its prime filters, is overt if and only if any element is nilpotent or not nilpotent (Proposition 12.51 in these notes of mine)....
4
votes
What does overtness mean for metric spaces?
To conjure up a non-overt space we must change slightly the definition of topology, since even inuitionistically every space is overt, so long as every union of opens is open.
Let $\Sigma$ be the ...
3
votes
What does overtness mean for metric spaces?
In computable analysis, the typical approach to metric spaces is that of a computable metric space. If we assume that there already is some external concept of the metric space we want to handle, we ...
2
votes
Condition to guarantee that an inhabited and bounded set of reals has a supremum
The following (somewhat strong) property seems to be sufficient:
For any open sets $U,V \subseteq \mathbb{R}$, if $\forall x \in \mathbb{R}.\; x \in U \vee x \in V$, then either $S \subseteq U$ or $S ...
2
votes
Is the Intermediate Value Theorem strictly stronger than LLPO?
In Lifschitz realizability $\mathbf{LLPO}$ holds but the intermediate value theorem fails.
The fact that $\mathbf{LLPO}$ holds is a standard property of Lifschitz realizability. The analytic version ...
Only top scored, non community-wiki answers of a minimum length are eligible
Related Tags
overt-spaces × 8gn.general-topology × 4
constructive-mathematics × 4
ct.category-theory × 3
lo.logic × 3
real-analysis × 2
computability-theory × 1
reverse-math × 1
noncommutative-topology × 1