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13 votes

Convex lattice polygons with equal area and perimeter

Pick's theorem says these two convex lattice polygons have area $$i+\frac{b}{2}-1 = 4 + 10/2 -1 = 8 \;,$$ and they both have perimeter $8 + 2 \sqrt{2}$. You can see I've "bumped out" two ...
Joseph O'Rourke's user avatar
13 votes
Accepted

Curve with no embedding in a toric surface

A generic curve of genus $5$ is not a hypersurface in a toric surface. This argument is going to use conceptual ideas from Haase and Schicho's paper "Lattice polygons and the number $2i+7$", ...
David E Speyer's user avatar
9 votes
Accepted

Volume of convex lattice polytopes with one interior lattice point

This is addressed in the 2013 paper (appeared in Advances in 2015) by Averkov, Krumpelmann, Nill. The give a sharp bound for the volume of a lattice simplex with one interior lattice point (Theorem 2....
Igor Rivin's user avatar
  • 96.4k
7 votes

Minimum weight triangulation of lattice points in a circle

I would like to propose a suggestion for finding some asymptotic bound, I think it should be $$\frac{1}{2}\cdot (2+\sqrt{2})\cdot \pi r^2.$$ Namely, the ratio of this number to the actual weight will ...
Dmitri Panov's user avatar
  • 28.9k
7 votes

There are at most four mutually visible lattice points—?

(Inspired by a meta thread on answers given in comments, I am recapping the answer given in the comments (1 2 3) as a CW answer.) The largest number of mutually visible points in $\mathbb{Z}^d$ is $2^...
7 votes
Accepted

Denominators of rational polytopes in terms of hyperplane coefficients

Let $x$ be a vertex of $\mathcal{P}$. By Cramer's rule, there is an $n \times n$ matrix $C$ such that each coordinate of $x$ is an integer multiple of $\frac{1}{|\det(C)|}$, and the absolute value of ...
Tony Huynh's user avatar
  • 32.1k
6 votes

A rational polytope that is not a 01-polytope?

Rather obvious in retrospect, but all 01-polytopes are inscribed (the vertices lie on a sphere). So if $P$ is non-inscribable, then it can't be a 01-polytope. There are non-inscribable rational ...
M. Winter's user avatar
  • 13.6k
5 votes
Accepted

Convex lattice polygons with equal area and perimeter

This answers question 2 as well. But I think both questions are way more suitable for math.stackexchange. I add another example because, unlike the first, it has the property that multiplied by $I^{n-...
Yaakov Baruch's user avatar
5 votes

Integer decomposition property with a partial order

A slightly more general combinatorial family that satisfies this is the family of $s$-lecture hall polytopes. These can be thought of as a weighted version of order polytopes. For a reference see ...
Gjergji Zaimi's user avatar
5 votes
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Edges of the contact polytope of the Leech lattice

Using the unimodular scaling of the Leech lattice, the length of each minimal vector is $\sqrt{4}$. Fixing a particular minimal vector $u$, the remaining minimal vectors $v$ are: 1 vector $v$ with $\...
Adam P. Goucher's user avatar
5 votes
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Minimum weight triangulation of lattice points in a circle

The examples shown below for $\ $ $r=4,\ 5,\ $ and $\ 6\ $ illustrate the idea described in Dmitri's answer. Some modifications in the interior plus the choices of edges near the boundary of the ...
Wlodek Kuperberg's user avatar
5 votes
Accepted

Are Minkowski sums of upward closed "convex" sets in $\mathbb{N}^k$ still "convex"? (WAS: Comparing mana costs in Magic: The Gathering)

It seems to me that all of the standard counter-examples to the polytope question easily adapt to be counter examples to this question: Take any polytopes in $\mathbb{Z}^{k-1}$ with $(A_0+B_0) \cap \...
David E Speyer's user avatar
5 votes

Volume of convex lattice polytopes with one interior lattice point

Depictions of the two lattice polyhedra mentioned so far (by Wlodek Kuperberg & js21):                     Left: $(0,0,0),(4,0,0),(0,4,0),(0,...
Joseph O'Rourke's user avatar
4 votes

Volume of convex lattice polytopes with one interior lattice point

Just to extend the examples so far: Given a non-decreasing list of $n$ integers $a_1 \leq a_2 \leq \cdots \leq a_n,$ consider the simplex with vertices at the origin and the points with all ...
Aaron Meyerowitz's user avatar
4 votes

I believe that all facets of a Voronoi-cell of a lattice are centerally symmetric. Is my argument correct? Is this true?

This is a community wiki answer based on the comments by alesia and Richard Stanley. You already gave the hardest part of the argument. To finish it off, note that translating by $\mathbf{l}$ the ...
4 votes

A rational polytope that is not a 01-polytope?

Every simplicial polytope is rational, hence there are infinitely many rational polytopes in any fixed dimension. In contrast, there are finitely many 0/1 polytopes, since they cannot have more than $...
Francisco Santos's user avatar
4 votes

Unimodality of $f$-vectors of $0/1$-polytopes

I have a partial answer, sadly I can't get fast enough f-vector computations to confirm my suspicions. Ziegler describes here some simple ways to get non-monotone f-vectors. Most of the constructions ...
Joseph Doolittle's user avatar
3 votes
Accepted

Bound on mutually x-ray-visible lattice points?

The largest number is $g(x,d) = (x+2)^d$, by an analogous argument as for visibility: if the differences of all coordinates of two points $A,B$ are divisible by $x+2$, then there are at least $x$ ...
Jan Kyncl's user avatar
  • 6,101
3 votes

Volume of convex lattice polytopes with one interior lattice point

this is a great question and fairly good answers are known for arbitrary dimensions. (I think there are works for $d=3$ but I am not sure.) The relevant papers are On lattice polytopes having ...
Gil Kalai's user avatar
  • 24.7k
3 votes

A source for $01$-polytopes

There's Ziegler's 1999 Lectures on 0/1-Polytopes, a 45 page survey on the arXiv. It is also the lead chapter in Polytopes - Combinatorics and Computation, Birkhäuser, 2000.
Brian Hopkins's user avatar
3 votes
Accepted

Convex Hulls of Demazure Modules

If I understand the question correctly, there is a nice description of the faces. They show up as so called reduced Kogan faces. However, taking the convex hull is not the right operation, as ...
Per Alexandersson's user avatar
3 votes
Accepted

Property of convex polygons on integer lattice structures

Consider the convex polygon with vertices $(0,0),(5,1),(4,4),(0,11),(-4,4),(-5,1)$. There are no lattice points on its boundary other than the six vertices. If you take any two that aren't adjacent, ...
Gerry Myerson's user avatar
2 votes

Integer decomposition property with a partial order

Have you checked the family of marked order polytopes? These include the classical Gelfand-Tsetlin polytopes, and I think I can construct such a partial order in case of GT-polytopes. Let $T \in kP_\...
Per Alexandersson's user avatar
2 votes

Number of vertices of a lattice reflexive polytope

This is due to a confusion about the notion of "smooth polytopes" in the literature. Casagrande's bound applies to simplicial polytopes. Reflexive polytopes come in pairs where -- if this ...
locally trivial's user avatar
2 votes

Convex lattice polygons with equal area and perimeter

My earlier comment "parallelogram and kite" was signaling an infinite family of examples of groups of $m$ convex lattice polygons where all of them from the same group have the same diameter,...
Wlod AA's user avatar
  • 4,786
1 vote
Accepted

How can I find the hyperplane passing through a 600-cell

You already could have considered your provided vertices within layers according to their last coord values. Within decreasing order you get: $(0, 0, 0; 1)$: the single point ...
Dr. Richard Klitzing's user avatar
1 vote

Integer decomposition property with a partial order

Just stumbled upon this question, pardon the necropost. There exist broad families of poset polytopes generalizing order and chain polytopes. These are known to have your IDP$\le$ property. The first ...
Igor Makhlin's user avatar
  • 3,513
1 vote

Problem with the vertices of a convex quadrilateral on integer lattice

I thought a few minutes on fedja's remark about a parallelogram contained inside the quadrilateral. It took me time to realize that you could "slide" an edge up with one point staying on one of the ...
Gerhard Paseman's user avatar

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