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10 votes
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If the closed unit ball of Banach space has at least one extreme point, must the Banach space the be a dual space?

Every separable Banach space $X$ can be equivalently renormed so that every point in the unit sphere is an extreme point: Take an injective bounded linear operator $T$ from $X$ into $\ell_2$ and use $|...
Bill Johnson's user avatar
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8 votes

If the closed unit ball of Banach space has at least one extreme point, must the Banach space the be a dual space?

No. Let $X$ and $Y$ be Banach spaces, and set $Z=X\oplus Y$, with $\||(x,y)|\|:=\|x\|+\|y\|$. Assume that $x$ is a extreme point of $X$ with $\|x\|=1$. Then $(x,0)$ becomes an extreme point of $Z$; ...
MSMalekan's user avatar
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4 votes
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A Banach space where the closed unit ball is the convex hull of its extreme points

The answer is "No" because there exist nonreflexive Banach spaces in which every point on the surface of the unit ball is extreme. See, for example, Diestel, Geometry of Banach spaces, Chapter 4, ...
August Cleaner's user avatar
3 votes
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Extremum placement for two-variable function

$\newcommand\R{\mathbb R}$ $$f(x,y)=\frac{2}{x^2+(y-1)^2+1}-\frac{1}{x^2+(y+1)^2+1} \tag{1}\label{1}$$ will do. Indeed, this function $f$ has exactly three critical points: a saddle point $(0,\approx-...
Iosif Pinelis's user avatar
3 votes
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On the extreme points of two convex sets

No: consider the line segments $\{0\}\times[-1,1]$ and $[-1,1]\times\{0\}$ in $\mathbb{R}^2$.
zeb's user avatar
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3 votes

Set of points covered by subspaces of small dimensions

Yes. One can take $C=2d+2$. I'll do the projective case, so my points will be nonzero points in a $d+1$-dimensional space $W$ and I'm looking for pairs of subspaces of total dimension $\leq d+1$ that ...
Will Sawin's user avatar
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2 votes

Extreme points of an intersection of convex set with countably many linear spaces

The last paragraph is wrong. Consider the case $m=1$. $\tilde{M}$ is the intersection of $K$ with one hyperplane. In general this will not contain any extreme point of $K$, so its extreme points ...
Robert Israel's user avatar
2 votes
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Question on the relation between the Lagrangian Multiplier $\mathcal{L}=r+\lambda g(r,\theta_1,\dotsc,\theta_{N-1})$ and the Hessian of $r$

If the constraint function $g$ allows to parametrize $r$ by $r = \varphi(\theta_1,\dots,\theta_{M})$ via the implicit function theorem, then you can rewrite your optimization problem as an ...
Hannes's user avatar
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2 votes

Extremum placement for two-variable function

Just draw a contour plot starting with a saddle: You can assign pretty much arbitrary value to each contour within the limits of common sense, so for an appropriate choice of values this diagram will ...
fedja's user avatar
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2 votes
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Regarding extreme point in a Banach space

Suppose that $x$ satisfies the condition and is not extreme in the unit ball of $X$. It means that we can write $x = \frac{y+z}{2}$ for some $y,z \in B_{X}$ different from $x$. Since $|\frac{1}{2}f(y)+...
Mateusz Wasilewski's user avatar
1 vote

Maximizing a skew-symmetric 4D cross product

Too long to comment. See if this helps. Since the matrix (defining the quadratic) is skew-symmetric, we can first decompose it into $Q\Sigma Q^\top$, where $Q$ is orthogonal, and $\Sigma$ is a block ...
DSM's user avatar
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