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2 votes

algebraic momentum map

This is an affirmative answer to $1$ (assuming by Hamiltonian you mean in the sense of real symplectic geometry). Yes. Due to Sumihiro's theorem (+ standard facts about Hamiltonians). In fact the assu …
Nick L's user avatar
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7 votes
Accepted

Symplectic reduction of 4-manifolds with circle actions

By a result of Hui Li https://arxiv.org/abs/math/0605133, the fundamental groups of $M_{red}$ and $M$ are isomorphic, so one can deduce the genus of $M_{red}$ from the fundamental group of $M$.
Nick L's user avatar
  • 6,995