Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with ct.category-theory
Search options not deleted
user 98863
Enriched categories, topoi, abelian categories, monoidal categories, homological algebra.
1
vote
What is known about the category of Hopf algebras?
Concerning the second question, if the algebra A is finite dimensional, a universal bialgebra analogous to End(A) is easily constructed, by considering a suitable quotient of the tensor algebra on the …
- 1,028
1
vote
Morita equivalent algebras in a fusion category
in the algebra case, B=eMn(A)e "because" B=End_A (P) with P f.g. proyective, so, finding e is the same as give a presentation of P as a direct summand of A^n. Also, P=F(B) where F is the functor givin …
- 1,028
4
votes
A toy example of a tensor triangulated category?
Take a finite dimensional Hopf algebra $H$, the category of $H$-modules is Frobenius (projectives=injectives and there is enough of both); e.g. take $H$ to be the group algebra of a finite group. So …
- 1,028
2
votes
Smooth affine algebras are Calabi-Yau
I don't think so. If A is commutative and of finite global dimension, say n, finitely generated as k-algebra, then by HKR you have $HH_n(A)\cong\Omega^n(A)$, and you want it to be isomorphic to $A$ as …
- 1,028