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For questions on modules over rings.

5 votes
Accepted

Naive question on tensor product

A trivial counterexample is $m=m'=0$. Perhaps more interesting is a situation where $b$ does not belong to the image of $A$, but some multiple or power of $b$ does. Say $M = B = \mathbb{C}[x]$ and $A …
Zach Teitler's user avatar
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