Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options not deleted user 8628
4 votes
1 answer
181 views

Cardinality of a set of pairwise non-order-isomorphic ultrafilters on $\omega$

It is well known that there are $2^{2^{\aleph_0}}$ many non-principal ultrafilters on $\omega$. … Is there a set ${\frak U}$ of non-principal ultrafilters on $\omega$ with $|{\frak U}| = 2^{2^{\aleph_0}}$ such that for ${\cal U}_1\neq {\cal U}_2\in{\frak U}$ the partially ordered sets $({\cal U}_1, …
Dominic van der Zypen's user avatar
1 vote
1 answer
79 views

Products of spaces with an underlying free ultrafilter as topology

If ${\cal U}$ is any ultrafilter on $\omega$, the pair $(\omega,{\cal U}\cup \{\emptyset\})$ is a connected topological space. Is there a non-principal ultrafilter ${\cal U}$ on $\omega$ such that we …
Dominic van der Zypen's user avatar
5 votes
1 answer
211 views

Relation between ultrafilters ${\scr U}$ and ${\scr U} \otimes {\scr U}$ [closed]

If ${\scr U}$ and ${\scr V}$ are ultrafilters on non-empty sets $A$ and $B$ respectively, then the tensor product ${\scr U}\otimes{\scr V}$ is the following ultrafilter on $A\times B$: $$\big\{X\subseteq …
Dominic van der Zypen's user avatar
4 votes
2 answers
367 views

Multiplicative and additive groups of the field $(\prod_{n\in\omega}\mathbb{Z}/p_n\mathbb{Z}...

Let ${\cal U}$ be a non-principal ultrafilter on $\omega$, and for each $n\in\omega$, let $p_n$ denote the $n$th prime, that is $p_0 = 2, p_1=3, \ldots$ Next we introduce the following standard equiva …
Dominic van der Zypen's user avatar
7 votes
1 answer
215 views

Are free ultrafilters as posets product-irreducible?

Let $\kappa\geq \aleph_0$ be a cardinal, and suppose that ${\cal U}$ is a non-principal ultrafilter on $\kappa$. We regard ${\cal U}$ as a poset $({\cal U}, \subseteq)$. Suppose that there are posets …
Dominic van der Zypen's user avatar
4 votes
1 answer
386 views

Models of $\mathsf{ZFC}$ with neither $P$- nor $Q$-points

A $P$-point is an ultrafilter $\scr U$on $\omega$ such that for every function $f:\omega\to\omega$ there is $x\in {\scr U}$ such that the restriction $f|_x$ is either constant, or finite-to-one. A $Q …
Dominic van der Zypen's user avatar
0 votes
1 answer
196 views

Maximal elements in the Rudin-Keisler ordering

(Ramsey ultrafilters do not necessarily exist.) Question. Does $\text{NPU}(\omega)/\simeq_{RK}$ have maximal elements? …
Dominic van der Zypen's user avatar
3 votes
2 answers
245 views

"Completion property" in $(\beta\omega,+)$

Let $\beta\omega$ be collection of all ultrafilters on $\omega$ (principal and non-principal). We endow $\beta\omega$ with an operation $+$ in the following way. …
Dominic van der Zypen's user avatar
4 votes
1 answer
254 views

Minimal cardinality of a filter base of a non-principal uniform ultrafilters

If ${\cal U, V}$ are non-principal uniform ultrafilters on $\kappa$, do we necessarily have $b({\cal U}) = b({\cal V})$? … Thanks to Joseph van Name for making me aware of uniform ultrafilters and the fact that this question is only (potentially) interesting when restricted to these. …
Dominic van der Zypen's user avatar
4 votes
1 answer
172 views

Maximal intersecting families on $\omega$ that are not ultrafilters

Let ${\frak U}$ be the collection of ultrafilters on $\omega$, and let ${\frak M}$ be the collection of maximal intersecting families on $\omega$. …
Dominic van der Zypen's user avatar
4 votes
1 answer
221 views

Addition and Rudin-Keisler ordering in $\beta \omega$

$\DeclareMathOperator{\RK}{\mathrm{RK}}$Let $\beta\omega$ be the Stone-Cech compactification of $\omega$ with the discrete topology. We can endow $\beta\omega$ with an addition operation that extends …
Dominic van der Zypen's user avatar
4 votes
0 answers
158 views

Finite pre-orders embeddable in the Rudin-Keisler ordering

Let $\NPU(\omega)$ be the set of non-principal ultrafilters on $\omega$. …
Dominic van der Zypen's user avatar
7 votes
1 answer
192 views

Non-tensor-representable ultrafilters on $\omega$

If ${\cal U}$ and ${\cal V}$ are ultrafilters on non-empty sets $A$ and $B$ respectively, then the tensor product ${\cal U}\otimes{\cal V}$ is the following ultrafilter on $A\times B$: $$\big\{X\subseteq … We say an ultrafilter ${\cal Z}$ on $\omega$ is Tensor-representable if there are non-Keisler-Rudin-equivalent ultrafilters ${\cal U}, {\cal V}$ and a bijection $\psi:\omega^2\to \omega$ such that ${\cal …
Dominic van der Zypen's user avatar
3 votes
2 answers
140 views

Is $(\omega+1)^\omega/{\cal U}$ complete for ${\cal U}$ free ultrafilter?

Let ${\cal U}$ be a free ultrafilter on $\omega$. Is the linearly ordered set $(\omega+1)^\omega/{\cal U}$ complete?
Dominic van der Zypen's user avatar
4 votes
1 answer
273 views

Supremum of infimum of measure of members of a free ultrafilter

Let $\text{FrU}(\omega)$ be the collection of free ultrafilters on $\omega$. …
Dominic van der Zypen's user avatar

15 30 50 per page